Triangle ABC has vertices A(−2, 5), B(1, 0), and C(6, −2). What are the coordinates of the vertices of △AʹBʹCʹ for Ry-axis?

Mathematics

1 answer:

OLga [1]4 years ago

6 0

Answer:

A'(2,5)

B'(-1,0)

C'(-6,-2)

Step-by-step explanation:

Triangle A(-2,5) , B(1,0) , C(6,-2) reflection in the y-axis is;

A(-2 + 4 , 5) = A'(2,5)

B(1 - 2 , 0) = B'(-1,0)

C(6 - 12 , -2) = C'(-6,-2)

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3 years ago

Read 2 more answers

Factor out the GCF from the terms of the polynomial –4y5 + 6y3 + 8y2 – 2y. A. –2y4 + 3y2 + 4y – 1 B. y(–4y4 + 6y2 + 8y – 2) C. 2

andreyandreev [35.5K]

Answer:

Option D) $-2y(2y^4-3y^2-4y+1)$ is correct

Therefore $-4y^5+6y^3+8y^2-2y=-2y(2y^4-3y^2-4y+1)$

Step-by-step explanation:

Given polynomial is $-4y^5+6y^3+8y^2-2y$

To factorise the given polynomial by taking out the common terms of the given polynomial :

$-4y^5+6y^3+8y^2-2y$
$=2y(-2y^4+3y^2+4y-1)$ ( here 2y is GCF common term so taking outside the terms of the polynomial )
$=-2y(2y^4-3y^2-4y+1)$ ( now taking (-) outside )