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babymother [125]
3 years ago
14

Triangle ABC has vertices A(−2, 5), B(1, 0), and C(6, −2). What are the coordinates of the vertices of △AʹBʹCʹ for Ry-axis?

Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer:

A'(2,5)

B'(-1,0)

C'(-6,-2)

Step-by-step explanation:

Triangle A(-2,5) , B(1,0) , C(6,-2) reflection in the y-axis is;

A(-2 + 4 , 5) = A'(2,5)

B(1 - 2 , 0) = B'(-1,0)

C(6 - 12 , -2) = C'(-6,-2)

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Write the equation of the line passing through (-3, 4) and normal to -2x + 7y = -3. (Note: normal means perpendicular)
MArishka [77]

Answer:

The answer to your question is     y = -7/2x -13/2

Step-by-step explanation:

Point = (-3, 4)

Line   -2x + 7y = -3

Process

1.- Solve equation for y to find the slope of the perpendicular line

                  7y = 2x - 3

                    y = 2/7 x - 3/7

slope = 2/7

Slope of the perpendicular line = -7/2

2.- Find the equation of the new line

                   y - y1 = m(x - x1)

                   y - 4 = -7/2(x + 3)

                   y - 4 = -7/2x - 21/2

                   y = -7/2x - 21/2 + 4

                   y = -7/2x -21/2 + 8/2

3.- Result

                   y = -7/2x -13/2

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