Question

The nth term of a sequence is 3n - 1. What are the first two terms?

Answer 1

Answer:

first term = 2

second term = 5

Step-by-step explanation:

n = 1 ; 3n - 1 = 3*1 - 1 = 3 - 1 = 2

n=2;   3n -1 = 3*2 - 1 = 6- 1 = 5

Answer 2

Step-by-step explanation:

Given :

$t_n = 3n - 1 \\ \\ \therefore \: t_1 = 3 \times 1 - 1 \\\therefore \: t_1 = 3 - 1 \\ \red{ \boxed{ \therefore \: t_1= 2}} \\ \\ t_2 = 3 \times 2 - 1 \\\therefore \: t_2 = 6 - 1 \\ \orange{ \boxed{ \therefore \: t_2= 5}}$

Hence, first two terms of given sequence are 2 & 5.