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Zielflug [23.3K]
3 years ago
10

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0

T(t) = T_s + (T_0 - T_s)e^{-kt}

T(t) - T_s = (T_0 - T_s)e^{-kt}

\dfrac{ T(t) - T_s}{T_0 - T_s} = e^{-kt}

\ln \dfrac{ T(t) - T_s}{T_0 - T_s} = -kt

k = - \dfrac{ \ln \dfrac{ T(t) - T_s}{T_0 - T_s} }{t}

OK now let's plug in the numbers.

We have t=15 minutes, T_0 = 80 C, Ts = 50, T(15)=60 C,

k = - \dfrac{ \ln \dfrac{ 60 - 50}{80 - 50} }{15 \textrm{ min}}

k = - \frac{1}{15} \ln \frac 1 3

k = \frac{1}{15} \ln 3

k \approx 0.07324 per minute

Answer: B


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PLZZZ HELP FOR BRAINLIST
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Step-by-step explanation:

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The average hourly charge of plumbers in the Denver area is $84.00 with a standard deviation of $4.00. Assume that the hourly ch
Simora [160]

Answer:

The probability is 0.31

Step-by-step explanation:

In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.

Firstly, we calculate the standard score of $86 using the mean and the standard deviation.

Mathematically;

z-score = (x-mean)/SD

where x = 86, mean = 84 and SD = 4

z-score = (86-84)/4 = 2/4 = 0.5

Hence, we want to calculate P(z ≥ 0.5)

Using standard table

P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854

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5 0
3 years ago
Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how
astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be x.

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

x=A\times (1+\frac{r}{100})^{11}

x=75000\times (1+\frac{2.2}{100})^{11}

x=75000\times (1+0.022)^{11}

x=75000\times (1.022)^{11}

x=75000\times 1.2704

x=95280.

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0
3 years ago
Minny has two coupons, but can use one of them. The first one is for $5 off an item; the second coupon is for 20% off an item. T
joja [24]
Let's first solve for the $5 off coupon,

28 - 5 = 23

The final total is $23.00 with $5 off.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Now for the final price of the 20% off coupon,

20\% = 0.2

0.2 or 0.20 is decimal form of 20%. Easier to multiply than in percent form!

0.2 \times 28 = 5.6

$5.6 or $5.60 is 20% of 28, we're not done yet!

Lastly, subtract 20% off of 28 (5.6) from 28,

28 - 5.6 = 22.4
$22.4 or $22.40 is the final after 20% off!

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Q. Which is less after the discounts??

$23.00 or $22.40

A. $22.40 of course which was the 20% off.

Part A : Which coupon should she use ?

Answer : Well, to get a lower price, less to pay, the 20% off coupon is better!

Part B: How much money will she save by using the better coupon?

Answer : $5.6 / $5.60 is the amount she'll save!

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

I hope that helps you out!!

Any more questions, please just ask me!!

~ Zoey
5 0
3 years ago
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