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choli [55]
3 years ago
10

8/9k + 9/5 = -4 - 9/7k

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0

Answer:

k=-1827/685

Step-by-step explanation:

8/9k+9/5=-4-9/7k

8/9k-(-9/7k)=-4-9/5

8/9k+9/7k=-20/5-9/5

56/63k+81/63k=-29/5

137/63k=-29/5

k=(-29/5)/(137/63)

k=(-29/5)(63/137)

k=-1827/685

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Answer:

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Step-by-step explanation:

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3 years ago
Help me I really need to get this done
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It’s the second one

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Find the product of z1 and z2, where z1 = 5(cos 60° + i sin 60°) and z2 = 7(cos 210° + i sin 210°)
Verizon [17]

Answer:

cos210=cos(180+30)=−cos30=−√32 . sin210=sin(180+30)=−sin30=−12 . 3(cos210+isin210) =3(−√32)+3i(−12). −(32)√3−(32)i. My favourite way of seeing that sin30=12 and cos30=√32 is ...

Step-by-step explanation:

But that's what I say personally

3 0
3 years ago
When s is the open hemisphere x 2 + y 2 + z 2 = 1, z ≤ 0 , oriented by the inward normal pointing to the origin, then the bounda
Anit [1.1K]
The figure below shows a diagram of this problem. First of all we graph the hemisphere. This one has a radius equal to 1. Given that z ≤ 0 a sphere will be valid only in the negative z-axis, that is, we will get a half of a sphere that is the hemisphere shown in the figure. We know that this hemisphere is oriented by the inward normal pointing to the origin, then we have a Differential Surface Vector called N, using the Right-hand rule <span>the boundary orientation is </span>counterclockwise.

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3 years ago
What is the factored form of 2x2 + x-3?
Vesnalui [34]

Answer:

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

2x^2+3x-2x-3=0

Group the first 2 terms together and the second 2 term together in order to factor:

(2x^2+3x)-(2x-3)=0 and factor out what's common in each set of parenthesis.

x(2x+3)-1(2x+3)=0

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

(2x+3)(x-1)=0

That matches your first choice

6 0
3 years ago
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