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Whitepunk [10]
2 years ago
12

Retype the statements, correcting the syntax error in each print statement. print('Predictions are hard.") print(Especially abou

t the future.) user_num = 5 print('user_num is:' user_num)
Engineering
1 answer:
marshall27 [118]2 years ago
3 0
Print(‘Predictions are hard’)
print(‘Especially about the future’)
user_num = 5
print(‘user_num is:’+str(user_num))

There are many ways to do the last print. Look up string interpolation
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Please help me do this with my exam tomorrow.
blagie [28]

Answer:

ddddddddddddddddddddddddddddd

Explanation:

cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

6 0
2 years ago
The operating sequence to light the main burners on an intermittent pilot system is:______.
11111nata11111 [884]
The pilot valve and spark igniter are energized, the pilot flame is proved, and then the main gas valve is energized.
7 0
1 year ago
A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 16.403
Dmitry [639]

Answer:

A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.

Explanation:

8 0
3 years ago
Find the following for an input of 120 VAC(RMS), 60 hertz, given a 10:1 stepdown transformer, and a full-wave bridge rectifier.
atroni [7]

Answer:

(i) 169.68 volt

(ii) 16.90 volt

(iii) 16.90 volt

(iv) 108.07 volt

(v) 2.161 A

Explanation:

Turn ratio is given as 10:1

We have given that input voltage v_p=120volt

(i) We know that peak voltage is give by v_{peak}=\sqrt{2}v_p=\sqrt{2}\times 120=169.68volt

(ii) We know that for transformer \frac{v_p}{v_s}=\frac{n_p}{n_s}

So \frac{169.08}{v_s}=\frac{10}{1}

v_s=16.90volt

So peak voltage in secondary will be 16.90 volt

(iii) Peak voltage of the rectifier will be equal to the peak voltage of the secondary

So peak voltage of the rectifier will be 16.90 volt

(iv) Dc voltage of the rectifier is given by v_{dc}=\frac{2v_m}{\pi }=\frac{2\times 1.414\times 120}{3.14}=108.07volt

(v) Now dc current is given by i_{dc}=\frac{v_{dc}}{R}=\frac{108.07}{50}=2.1614A

4 0
2 years ago
What tool should be used to loosen or tighten brake or fuel lines?
emmainna [20.7K]

The tool you would use are brake line wrenches.

4 0
3 years ago
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