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alukav5142 [94]
3 years ago
11

Steam enters a heat exchanger at a pressure of 1.5 bar and a temperature of 400°C with a mass flow rate of 0.05 kg/s and exits a

t a temperature of 120°C and at the same inlet pressure. The steam heat transfer takes place with refrigerant R22 in a separate stream. The refrigerant enters the heat exchanger as liquid at 4.5 bar and leaves at the same pressure and at a temperature of 10°C. The heat exchanger is not well designed and there is stray heat transfer to the surroundings equal to 10% of the heat transferred from the steam.
Determine

(a) The rate of stray heat transfer, in kW.

(b) The rate of heat transfer to the refrigerant, in kW

(c) The mass flow rate of the refrigerant, in kg/s

Engineering
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

a. 2.832kw

b. 25.488kw

c. 0.118kg/s

Explanation:

Please look at attachment carefully

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Explain the LWD process why is it important in drilling operations?
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Answer:

Logging while drilling (LWD) is a technique of conveying well logging tools into the well borehole downhole as part of the bottom hole assembly (BHA). ... In these situations, the LWD measurement ensures that some measurement of the subsurface is captured in the event that wireline operations are not possible.

Explanation:

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6 0
2 years ago
What is the resistance of a resistor if the current flowing through it is 3mA and the voltage across it is 5.3V?
Flura [38]

Answer: 1766.667 Ω = 1.767kΩ

Explanation:

V=iR

where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).

3mA = 0.003 A

Rearranging the equation, we get

R=V/i

Now we are solving for resistance. Plug in 0.003 A and 5.3 V.

R = 5.3 / 0.003

= 1766.6667 Ω

= 1.7666667 kΩ

The 6s are repeating so round off to whichever value you need for exactness.

6 0
1 year ago
A family member who hasn’t worked with computers before has decided to change jobs. You’ve been asked to explain some of the bas
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That due to the specific tasks that needs to be accomplished by each program to make an all encompassing program would be inefficient and full of bugs
6 0
3 years ago
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Each of the following activities are commonly performed during the implementation of the Database Life Cycle (DBLC). Fill in the
kicyunya [14]
Yessiree I agree with yu cause yu are right
4 0
3 years ago
Determine the hydraulic radius for the following rectangular open channel width =23m water depth =3m
Romashka-Z-Leto [24]

Answer:

2.379m

Explanation:

The width = 23m

The depth = 3m

The radius is denoted as R

The wetted area is = A

The perimeter perimeter = P

Hydraulic radius

R = A/P

The area of a rectangular channel

= Width multiplied by Depth

A = 23x3

A = 69m²

Perimeter = (2x3)+23

P = 6+23

P= 29

Hydraulic radius R = 69/29

= 2.379m

This answers the question

Thank you!

8 0
2 years ago
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