Answer:
a)  23.551 hp
b)  516.89 hp
Explanation:
<u>given:</u>

<u>required:</u>
the power in hp
<u>solution:</u>
.............(1)
by substituting in the equation (1)
          =353.27 lbf
..........(2)
by substituting in the equation (2)
          = 2769.29 lbf
power is defined by 
               P=F.V
      
353.27*36.67
            =12954.411 lbf.ft/s
            =12954.411*.001818
            =23.551 hp
       
2769.29*102.67
            = 284323 lbf.ft/s
            = 284323*.001818
            = 516.89 hp
 
        
             
        
        
        
Answer:
401.3 kg/s
Explanation:
The power plant has an efficiency of 36%. This means 64% of the heat form the source (q1) will become waste heat. Of the waste heat, 85% will be taken away by water (qw).
qw = 0.85 * q2
q2 = 0.64 * q1
p = 0.36 * q1
q1 = p /0.36
q2 = 0.64/0.36 * p
qw = 0.85 *0.64/0.36 * p
qw = 0.85 *0.64/0.36 * 600 = 907 MW
In evaporation water becomes vapor absorbing heat without going to the boiling point (similar to how sweating takes heat from the human body)
The latent heat for the vaporization of water is:
SLH = 2.26 MJ/kg
So, to dissipate 907 MW
G = qw * SLH = 907 / 2.26 = 401.3 kg/s