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alukav5142 [94]
3 years ago
11

Steam enters a heat exchanger at a pressure of 1.5 bar and a temperature of 400°C with a mass flow rate of 0.05 kg/s and exits a

t a temperature of 120°C and at the same inlet pressure. The steam heat transfer takes place with refrigerant R22 in a separate stream. The refrigerant enters the heat exchanger as liquid at 4.5 bar and leaves at the same pressure and at a temperature of 10°C. The heat exchanger is not well designed and there is stray heat transfer to the surroundings equal to 10% of the heat transferred from the steam.
Determine

(a) The rate of stray heat transfer, in kW.

(b) The rate of heat transfer to the refrigerant, in kW

(c) The mass flow rate of the refrigerant, in kg/s

Engineering
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

a. 2.832kw

b. 25.488kw

c. 0.118kg/s

Explanation:

Please look at attachment carefully

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The one that is not an option of the 3 technology bets made are  Digital core and Design Thinking.

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8 0
2 years ago
The denominator of a fraction is 4 more than the numenator. If 4 is added to the numenator and 7 is added to the denominator, th
kati45 [8]

Answer:

\frac{3}{7}

Explanation:

Lets take the numerator of the fraction to be = x

So the denominator of the fraction is 4 more than the numerator = x+4

The fraction is ;\frac{x}{4+x}

Now add 4 to the numerator and add 7 to the denominator as;

\frac{x+4}{4+x+7} =\frac{x+4}{x+11}

This new fraction is equal to 1 half =1/2

write the equation as;

\frac{x+4}{x+11} =\frac{1}{2}

perform cross-product

2(x+4 )=1( x+11 )

2x+8 = x + 11

2x-x = 11-8

x=3

The original fraction is;  

\frac{x}{4+x} =\frac{3}{3+4} =\frac{3}{7}

3 0
3 years ago
A turbine operates at steady state, and experiences a heat loss. 1.1 kg/s of water flows through the system. The inlet is mainta
strojnjashka [21]

Answer:

\dot W_{out} = 399.47\,kW

Explanation:

The turbine is modelled after the First Law of Thermodynamics:

-\dot Q_{out} -\dot W_{out} + \dot m\cdot (h_{in}-h_{out}) = 0

The work done by the turbine is:

\dot W_{out} = \dot m \cdot (h_{in}-h_{out})-\dot Q_{out}

The properties of the water are obtained from property tables:

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P = 10\,MPa

T = 520\,^{\textdegree}C

h = 3425.9\,\frac{kJ}{kg}

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P = 1\,MPa

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h = 3008.2\,\frac{kJ}{kg}

The work output is:

\dot W_{out} = \left(1.1\,\frac{kg}{s}\right)\cdot \left(3425.9\,\frac{kJ}{kg} -3008.2\,\frac{kJ}{kg}\right) - 60\,kW

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5 0
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Pointssss 100 and brainliest :)
Delvig [45]

Answer:

thank you for the free point have a great rest of your day

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Which phrase best describes a safety-critical system? A. a system that faces a very high risk of failure B. a system isolated fr
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Answer:

B.

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