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Readme [11.4K]
3 years ago
14

Which viral replication cycle is represented in part A of this diagram?

Biology
1 answer:
Burka [1]3 years ago
5 0

Answer:

The correct answer is - option D. lytic cycle.

Explanation:

The lytic cycle is one of the two viral reproduction cycle. Generally, it is the major reproduction cycle. In this cycle reproduction of the viruses takes place inside the host cell and produce more viruses. In the production of the more viruses the host cell and it''s destruction takes place in the end. The 5 steps that takes place are as follows:

1- attachment - viruses attach to the cell.

2-penetration- only nucleic acid or genetic material is injected into the host cell through the hole made by the tail fibers and enzymes.

3- synthesis - replication of viral nucleic acid and protein and envelope.

4- assembly - assembling of the new viruses formed.

5- release.

Thus, the correct answer is - option D.

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Porque un grupo de celulas pequeñas ayudarian a un organismo a mantener la homeostasis mejor que una celula grande?
NeX [460]

Answer:  

Una parte fundamental de la homeostasis es la transferencia y la ingesta de moléculas (sea necesario o no). Es importante que la célula pueda llevar los nutrientes necesarios inmediatamente donde los necesita y poder deshacerse de los subproductos dañinos del proceso celular. Es igualmente importante poder regular la concentración de agua. Las células más pequeñas tienen una superficie más grande en relación con su volumen (su superficie se escala con R ^ 2 mientras que su volumen con R ^ 3 donde R es el radio de una célula) y, por lo tanto, los intercambios a lo largo de la membrana celular se ven favorecidos en comparación con las células más grandes que necesitan muchos intercambios pero tienen proporcionalmente menos área de membranas. Si bien A no es necesariamente cierto, C es definitivamente cierto y, por lo tanto, la respuesta correcta.

5 0
3 years ago
What problems might result from the prolonged administration of cortisol to a person with severe inflammatory disease?
ki77a [65]

Answer:

The prolonged exposure to cortisol hormone may cause different health problems including anxiety, depression, muscle atrophy, hypertension, metabolic problems, diabetes, myopathies, osteoporosis, etc.

Explanation:

Cortisol is a stress hormone secreted by the adrenal glands, it is a steroid hormone that is involved in diverse functions including the control of metabolic and immune responses, salt balance (blood pressure), etc. Moreover, cortisol hormone also has anti-inflammatory properties. However, prolonged exposure to stress hormones like cortisol is associated with different health problems, especially anxiety and depression.

3 0
3 years ago
1. All cells are derived from _____________________
Inessa [10]
1.other cells
2. Growth, reproduction
4.nucleus
6. It makes 2
10.46
——————————-

5. Sex chromosomes
6. XX is female, XY is male

—————
3.zygote
4. No


5 0
3 years ago
Organisms have the ability to regulate their internal environment in order to maintain a steady state called _____.
castortr0y [4]
Homeostasis 

Hope this helps

7 0
3 years ago
Read 2 more answers
You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo
irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype     Observed(O)    Expected (E)    O-E      (O-E)2     (O-E)2/E

Blue                 42                   43.44               -1.44       2.0736     0.0477

cyan                86                   83.46                 2.54     6.4516     0.0773

green              39                    40.1                    -1.1       1.2100      0.0302

Total              167                     167                                               0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

4 0
3 years ago
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