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vlabodo [156]
3 years ago
12

Suppose that you are in charge of designing a fracking job site. Which of these locations would be most ideal for the site?

Biology
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

B. On a flat, vacant plot in the outskirts of the city

Explanation:

Fracking, also known as hydraulic fracturing is a drilling method used in the oil and gas industry of most countries. It is the process whereby natural gas and petroleum is extracted from deep down the Earth. A crack is made in the rock layers, followed by the injection of a liquid called fracking liquid, which is usually water, at a very high pressure.

The process of fracking has serious environmental side effects e.g. release of harmful gases, noise pollution, water contamination etc. and hence, when choosing a fracking site, environment's sustainability and safety of people should be taken into account. This is why a fracking site cannot be designed in a residential city or around a neighborhood. The site should rather be designed in a location where it would pose a minimal environmental threat to the people e.g flat, vacant plot in the outskirts of the city

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Why did most mosquitoes perish when DDT was sprayed the first time?
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Answer:

Due to no resistance.

Explanation:

Most mosquitoes perish when DDT chemical was sprayed the first time because these mosquitoes are vulnerable to the DDT chemical and there is no resistance present in their body against this chemical. DDT chemical is an insecticide which is used against insects or pests that causes damage to human, organisms and crops. DDT was first synthesized in 1874 by the Austrian chemist named Othmar Zeidler.

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3 years ago
¿Cuántos gramos de dióxido de carbono (CO2) se producen si se quema 40 gramos del hidrocarburo ( C3H8 )?
Valentin [98]

Answer:

120 gramos de CO₂

Explanation:

La ecuación química balanceada para la reacción de combustión del hidrocarburo C₃H₈ (propano) es la siguiente:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Por lo tanto, 1 mol de C₃H₈ produce 3 moles de CO₂. Ahora debemos convertir las moles a gramos utilizando el peso molecular (PM) de cada compuesto:

PM(C₃H₈)= (3 x 12 g/mol) + (8 x 1 g/mol) = 44 g/mol

1 mol C₃H₈ = 1 mol x 44 g/mol = 44 g

PM(CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

3 mol CO₂ = 3 mol x 44 g/mol = 132 g

Por lo tanto, se producen 132 gramos de CO₂ a partir de 44 gramos de C₃H₈ y la relación estequiométrica es:

3 mol CO₂/1 mol C₃H₈ = 132 g CO₂/44 g C₃H₈

Finalmente, para calcular cuántos gramos de CO₂ se producen al quemar 40 g de C₃H₈, multiplicamos la relación estequiométrica por la masa a quemar:

masa CO₂ producida = 40 g C₃H₈ x 132 g CO₂/44 g C₃H₈= 120 g

3 0
3 years ago
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