Question

Use the graph of f(x)=x^2 to find a number δ such that ∣x^2−1∣<0.1 whenever 0<|x−1|<δ.

Answer 1

Answer:

$\delta=0.0333$

Step-by-step explanation:

$|x^2-1}=|x-1||x+1|$

$|x|-|1|$

$|x|$

$|x+1|$

Hence

$|x-1|$

$|x-1|$

Hopefully you get what I meant!!