Answer: if the y intercept is 3 it would be the one that has a point at 3 on the y intercept and from that point a rise of 2 and a run of 3
Step-by-step explanation:
Answer:
this is hi ow my teacher taught me put the whole numbers on one side and the fractions on the other the find a common denominator then add all together if it ends up a improper fraction convert to mixed number then add whole numbe and fraction and if the new mixed number has a number add bvb it t ok the whole number then combine to face your final anwser
Answer:
0.4444 = 44.44% probability that the sum of the two numbers is greater than 3 but less than 7.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
A number is selected at random from each of the sets {2,3,4} and {1, 3, 5}.
The possible values for the sum are:
2 + 1 = 3
2 + 3 = 5
2 + 5 = 7
3 + 1 = 4
3 + 3 = 6
3 + 5 = 8
4 + 1 = 5
4 + 3 = 7
4 + 5 = 9
Find the probability that the sum of the two numbers is greater than 3 but less than 7?
4 of the 9 sums are greater than 3 but less than 7. So

0.4444 = 44.44% probability that the sum of the two numbers is greater than 3 but less than 7.
You want to put this in the form (x+b)^2 + c
To do this take half of the coefficient of b from the ordinal form which is 6/2=3 as use this as your new b
This give you (x+3)^2.
If you foil this out you get x^2 +6x +9 so you have added 9 to the original expression so now all you need to do is subtract 9 to keep things balanced
The final expression then is (x+3)^2 -9
<u> So c= -9</u>
Answer:
True
Step-by-step explanation:
Suppose you have a quadratic function

Factoring this expression results in:

Where h and k are real numbers.
Then the function is equal to 0 when
and when
.
Therefore h and k will always be the solutions when we have the quadratic function factored in the form
Since we have ensured that the factors of the function contain only real numbers, then h and k are real numbers, and x and y must also be real numbers. Therefore solutions to an equation in this form will always be real solutions.
The statement is true