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Sveta_85 [38]
3 years ago
10

Harrison has 11 crayons. Does he have an even or odd number of crayons? Explain.

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
5 0

Answer:odd has there is one number alone if you put them in pairs


Step-by-step explanation:


densk [106]3 years ago
5 0

No it’s not equal because if you pair them each up two by two you’ll have one remainder left.


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I need help..... please
Bogdan [553]

Answer:

Step-by-step explanation:

I would say Town residents

5 0
3 years ago
What is the solution, if any, to the inequality |3x|2O?
Lera25 [3.4K]

Answer:

No solutions

Step-by-step explanation:

8 0
3 years ago
In the figure, △ABC is similar to △DEF. what is m∠1
Nady [450]

Answer:

C. 139°

Step-by-step explanation:

Given:

m<A = 62°

m<B = 77°

Required:

Find m<1

Solution:

Since ∆ABC is similar to ∆DEF, therefore:

<A ≅ <D, which means m<D = 62°

<B ≅ <E, which means m<E = 77°

<C ≅ <F

Therefore, based on exterior angle theorem:

m<1 = m<D + m<E

m<1 = 62° + 77° (substitution)

m<1 = 139°

7 0
3 years ago
Difference Between ten and a number is the sum of eight and number <br> Help !!?
Murrr4er [49]

Answer:

x = 1

Step-by-step explanation:

We will represent the unknown number as x

10 - x = 8 + x

Add x to both sides

10 - x + x = 8 + x + x

10 =  8 + 2x

Subtract 8 from both sides

10 - 8 = 2x

2 = 2x

Divide both sides by 2

1 = x

x = 1

3 0
4 years ago
SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council
fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = \frac{x-1100}{200}

P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517

4 0
4 years ago
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