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-Dominant- [34]
3 years ago
15

If f={(1, 2), (2, 3), (3,4),(5, 6), (6, 7). what is the range?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:

[1,2,3,5,6} Is the answer.

Step-by-step explanation:

I took this test earlier today .

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Whats the answer to this question
Liono4ka [1.6K]

Answer:

I believe it would be B.

Step-by-step explanation:

Range: area of variation with real numbers

Also, seeing the quadrant it is in means there are negative numbers. This takes out the possibility of option A.

4 0
3 years ago
Patty made a banner that has an area of 175 square inches. The length and width of the banner are whole numbers. The length is 7
Leviafan [203]

Answer:

Length = 35

w = 5

Step-by-step explanation:

l x w = area

7y x y = 175

7y^2 = 175

y^2 = 175/7

y^2=25

y=5

The length is 7y, so it's 5 times 7 or 35.

The width is just y, so it's 5.

6 0
2 years ago
Which trend line has been drawn correctly using the divide-center method?
dangina [55]

Answer:

I'm pretty sure its C but some please correct me if I'm wrong.

3 0
3 years ago
Read 2 more answers
Can someone help with graphs
amm1812

Answer:

here u go..............

5 0
2 years ago
Question B,C and D I need answers to these parts.
Alik [6]
Explanation<h2>Part b</h2>

So in part (b) we must give the annual growth factor. For any quantity that increases annualy, this factor is the number by which the quantity multiplies itself every year. For a given quantity that increases at a rate of p% its growth factor is given by:

1+\frac{p}{100}

In this case the production of ethanol increases at a rate of 5.5% per year which means that the growth factor is:

1+\frac{5.5}{100}=1.055

Then the growth factor and answer to part (b) is 1.055.

In part (c) we must write an equation that models the increase in the ethanol production. Given an initial qunatity Q and an annual growth factor k the quantity after x years is given by multiplying the initial quantity by the growth factor raised to the x. Then we get:

C(x)=Q\cdot k^x

In this case we need a function for the amount of ethanol produced E, x years after 1990. The 0.9 billion gallons produced that year compose our initial quantity and knowing that the annual growth factor is 1.055 we have the desire equation:

E(x)=0.9\cdot1.055^x

And that's the answer to part (c).

In part (d) we have to compare the actual production of ethanol in 2008 to the one predicted by the equation of part (c). Remember that x represents the years passed after 1990 so for the year 2008 the value of x is given by:

x=2008-1990=18

So the number we are looking for is E(18):

E(18)=0.9\cdot1.055^{18}=2.359

So the production estimated for 2008 is 2.359 billions of gallons. Then the actual production of 9 billion gallons is higher than the one predicted by our equation.

5 0
1 year ago
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