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Troyanec [42]
3 years ago
8

The side chain (r group) of the amino acid serine is ch2oh. The side chain of the amino acid leucine is ch2ch(ch3)2. Where would

you expect to find these amino acids in a globular protein in aqueous solution?
Chemistry
1 answer:
wel3 years ago
8 0

The answer is leucine would be in the interior, and serine would be on the exterior of the globular protein.

The side chain (R group) of the amino acid serine is CH₂OH. The side chain of the amino acid leucine is CH₂CH(CH₃)₂. In globular protein, leucine found in the interior, and serine found on the exterior. The nature of side chain decides the amino acid position in the globular protein , as CH₂CH(CH₃)₂ this is hydrophobic and CH₂OH is hydrophlic.

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Answer:

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What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
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Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

8 0
3 years ago
How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space
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Explanation:

An easy problem to solve with the Ideal Gases Law:

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Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K

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7 0
3 years ago
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Mice21 [21]
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