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Scrat [10]
3 years ago
6

I have no clue to what I even need to do.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}

\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r

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