Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
The answer is (9c/5)+32=F
1. The point where x and y axis meet is the intersect, origin of the coordinate system (0,0)
2. m<A and m<D = 90 then <A and D are complementary angles
3. 180 angle or linear rays
4. Obtuse angle measure more than 90
5. Segment of equal lengths are congruent segments
6. Lines that meet at a 90 angle are perpendicular
Answer: a. f(n+1) = f(n) + 20
Step-by-step explanation: