Answer:
A shaded region below a dashed line (y <3x-4)
Step-by-step explanation:
For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.
Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.
In this case what we have here is an open region, as the graph below shows.
3x-y>4 =-y>4-3x∴y<3x-4
Setting a value for x
3x-4=0
3x=4
3x/3=4/3
x=4/3 (slope)
(4/3,0)
<span>In statistics finding percentiles relates to the standard deviation and something called a z-score. For normally distributed data the z-score represents how many standard deviations above or below the mean that group is a part of. The z-score for normally distributed data for the 90th percentile is 1.28. The standard deviation is then multiplied by the z-score to find, in this case, the shotlrtest height needed to be in the 90th percentile of this population. In this case to be in the 90th percentile your height must be 60.27 inches.</span>
1 25.5
2 making two assumptions that the two triangle are identical and the figure on the left is a square then I’d say 57 but that not there so you might want to email your teacher.
3 35
The best option is C. Provide multiple worksheets with pictures of the basic shapes for children to colour.
<h3>What does the learning process in children involve?</h3>
The process of learning has often been described to include all but not limited to the following:
- gaining new understanding,
- learning new behaviours,
- skills,
- values, attitudes, and
- preferences.
Children according to experts learn faster and easily remember what they see. Hence, providing multiple worksheets with pictures of the basic shapes for children to colour is the most cost-efficient strategy to support children in learning about shapes.
You can learn more from a related question about teaching strategies to use for children here brainly.com/question/240537
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1/50? I can’t be sure....
Ok, so.. first you write both the problems down and write the 10 as a fraction (so it would automatically be 10/1). Then invert so it would be a multiplication problem (1/5 x 1/10). Since you can’t cross cancel, you multiply across. So, 1/5 x 1/10 (1 x 1 and 10 x 5)
1/50
