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irga5000 [103]
3 years ago
9

What is ​ BC ​? Enter your answer in the box.

Mathematics
2 answers:
Sati [7]3 years ago
6 0
Because the angles are congruent, the two legs are congruent.

8x-4= 5x + 11

Add 4 to both sides.

8x=5x + 15

Subtract 5x on both sides.

3x=15

Divide 3 on both sides.

x=5br />
Enter 5 into BC.

4x-2 />
4(5)-2

20-2= 18 />
18 is the answer.

I hope this helps!
~kaikers


mario62 [17]3 years ago
4 0
8x - 4 = 5x + 11
8x - 5x = 11 + 4
3x = 15
x = 5

BC = 4*5 - 2 = 20 - 2 = 18 units
 
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Which ordered pairs make both inequalities true? Check all that apply.
Thepotemich [5.8K]
All others did not satisfy the inequality simultaneously except #4 and #6
For #4:
2 < 5(1) + 2 i.e. 2 < 7 (true)
2 >= 1/2(1) + 1 i.e. 2 >= 3/2  (true)
For #6
2 < 5(2) + 2 i.e. 2 < 12 (true)
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7 0
3 years ago
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Y=-5x – 26<br> 15y=3x – 18
harina [27]

Answer:

Y = − 5 x − 26

y = x /5 − 6 /5

Step-by-step explanation:

4 0
3 years ago
Applying the concepts. Need help finding the value.
luda_lava [24]

we can use formula

log_ab=\frac{ln(b)}{ln(a)}

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(3)}{ln(2)}*\frac{ln(4)}{ln(3)}*\frac{ln(5)}{ln(4)}*\frac{ln(6)}{ln(5)}*\frac{ln(7)}{ln(6)}*\frac{ln(8)}{ln(7)}

now, we can cancel terms

and then we can simplify it

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(8)}{ln(2)}

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{ln(2^3)}{ln(2)}

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=\frac{3ln(2)}{ln(2)}

now, we can simplify it

and we get

log_23*log_34*log_45*log_56*log_6 7 *log_7 8=3...........Answer

5 0
3 years ago
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snow_lady [41]

Answer:

8     9.8 - 6.4n

9      15 - j/2

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8

2.8 - 4.4n - 2n +7

= 2.8+7 -4.4n -2n

= 9.8 - 6.4n

9

11 + (-3) - 1/8 j - 3/8 j +7

= 11 - 3 - 1/8 j - 3/8 j + 7

= 11 - 3 + 7 - 1/8 j - 3/8 j

= 15 - 4/8 j

= 15 - j/2

5 0
2 years ago
Which set of three numbers could be the side lengths of a triangle?
dusya [7]

B is the answer. The sum of two triangle legs should be more than the legth of the third.
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3 years ago
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