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So 5^2 -4^2 is 25-16 which is 9
6^2/9 is 36/9 which is 4 +9 is 13
13(13) is 169
6*6=36. he can line the jars pu 36 diff ways.
Answer:
So, the first three nonzero terms in the Maclaurin series are:

Step-by-step explanation:
From exercise we have the next function y = 6 sec(3x).
We know that Maclaurin series for the function sec x, have the following form:

So, for the given function y = 6 sec(3x), we get:

So, the first three nonzero terms in the Maclaurin series are:
