Just to make it easier on you It’s C.Pressure
The change in temperature was [ (37) - (-5) ] = 42 Fahrenheit degrees.
Kelvins and Celsius degrees are 9/5 (or 1.8) the size of Fahrenheit degrees.
42 F-degrees / 1.8 K per F-degree =<em> 23 and 1/3</em> Kelvins.
<u>Check,</u> using °C = (5/9) (°F - 32) and K = 273.15 + °C :
-5° F = -20.566° C = 252.594 K.
+37° F = 2.778° C = 275.928 K
(275.928K - 252.594K) = <u>23.334 K</u> close enough yay !
Mercury
Good luck on this!
Have fun
Answer:
d = v² / (2μ g)
Explanation:
In the work relationship is equal to the variation of energy,
W = ΔEm
The work is defined by
W = F. d = F d cos θ
In this case the outside is the force of friction, which always opposes
to the movement, so the angle is 180 °
W = - fr d
The force of friction can be found with Newton's second law
fr = μ N
Y Axis
N- W = 0
N = mg
fr = μ m g
We substitute in the expression of work
W = - μ mg d
Now we use the relationship of work and energy
-μ mg d = 0 -½ m v²
d = v² / (2μ g)
Answer:
The dog catches up with the man 6.1714m later.
Explanation:
The first thing to take into account is the speed formula. It is , where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is
Now, the distance equation for the man would be:
The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.
For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:
Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.
The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.
That value is used in the man's distance equation.
Finally, the dog catches up with the man 6.1714m later.