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siniylev [52]
3 years ago
9

What does a water wave transfer

Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
6 0
Vibrations of electric and magnetic fields
alexira [117]3 years ago
5 0
Energy is transferred through vibrations of electric and magnetic fields. Also, in sound waves, energy is transferred through vibration of air particles or a soild of which the sound travels though. Thus in this case, water waves would be transferred through the vibration of the water particles.
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3 years ago
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When the mass of an object increases, the forcé of gravity<br>​
diamong [38]

Answer:

increace

Explanation:

they are both going up

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What color will a yellow banana appear when illuminated by yellow light
Phantasy [73]

Answer:

A yellow banana reflects only yellow light,

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3 years ago
a student is pushing a 50 kilogram cart with a force of 500 newtons another students measures the speed of the cart and finds th
Irina-Kira [14]

The force of friction is 300 N

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write

\sum F = ma

where

\sum F is the net force acting on the object

m is its mass

a is its acceleration

For the cart in this problem, we have two forces acting on it:

- The force of push, F = 500 N, forward

- The force of friction, F_f, backward

So Newton's second law can be rewritten as

F-F_f = ma

where

m = 50 kg

a=4 m/s^2 is the acceleration of the cart

And solving for F_f, we find the force of friction:

F_f = F-ma=500-(50)(4)=300 N

Learn more about force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

4 0
3 years ago
The mass of the earth is 5.96/10kg^24. The radius of the earth is approximately 6.37x10^6 calculate the force of gravity
n200080 [17]
<h2>Answer:g=9.79ms^{-2},A object of mass m at the surface of earth experiences a force mg</h2>

Explanation:

Let M be the mass of earth.

Let R be the radius of earth.

Let G be the universal gravitational constant.

Given,

M=5.96\times 10^{24}Kg

R=6.37\times 10^{6}m

G=6.67259 \times 10^{-11}Nm^{2}Kg^{-2}

Let g be the acceleration due to gravity.

Then,g=\dfrac{GM}{R^{2}}

g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}

g=9.79ms^{-2}

A object of mass m at the surface of earth experiences a force mg

3 0
4 years ago
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