A 0.5 Kg block of ice at -20 °C was given 10,000 J of heat. Would this block of ice melt?
1 answer:
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<u>Answer:</u> The average atomic mass of the given element is 20.169 amu.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of the isotopes each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
- For isotope 1:
Mass of isotope 1 = 19.99 amu
Percentage abundance of isotope 1 = 90.92 %
Fractional abundance of isotope 1 = 0.9092
- For isotope 2:
Mass of isotope 2 = 20.99 amu
Percentage abundance of isotope 2 = 0.26%
Fractional abundance of isotope 2 = 0.0026
- For isotope 3:
Mass of isotope 3 = 21.99 amu
Percentage abundance of isotope 3 = 8.82%
Fractional abundance of isotope 3 = 0.0882
Putting values in equation 1, we get:
Hence, the average atomic mass of the given element is 20.169 amu.
The pressure exerted by the block on the table is given by:
where W is the weight of the box, and A is the bottom surface area of the box.
The weight of the box is:
Substituting into the first equation, we find the pressure: