All categories

3 years ago

Why are the noble gases (group 18) inert?

Chemistry

1 answer:

dalvyx [7]3 years ago

8 0

The noble gases are relatively unreactive because they have a stable octet of valence electrons.

Thus, they do not tend to undergo reactions in which they will gain or lose valence electrons,

However, <em>only He, Ne, and Ar are inert</em>. Kr and Xe combine with other highly reactive elements to form stable compounds.

You might be interested in

The Himalayan mountain range of India was formed at a ____.

Rzqust [24]

Answer:

its answer is b

Explanation:

divergent boundary

7 0

3 years ago

Read 2 more answers

Which of these happens when the warm water gets to the North and South Poles

Airida [17]

Answer:It creates a heat source on the cold water and the molecules act against each other and then it becomes steam.

Explanation:I had to take this on a test.

6 0

3 years ago

List two products derived from ethylene

laiz [17]

Ethylene is the starting material for the preparation of a number of two-carbon compounds including ethanol (industrial alcohol), ethylene oxide (converted to ethylene glycol for antifreeze and polyester fibres and films), acetaldehyde (converted to acetic acid), and vinyl chloride (converted to polyvinyl chloride).

8 0

2 years ago

10 Give the symbol and Latin name of the following elements

Romashka-Z-Leto [24]

Answer:

Explanation:

Antimony- sb and the latin name: stibium

Copper- Cu and the latin name: cuprum

Gold- Au and the latin name: Aurum

Mercury- Hg and the latin name: hydrargyrum

Tron- There is no such element as tron

Lead- Pb and the latin name: plumbum

Potassium- K and the latin name: kalium

Silver- Ag and the latin name: argentum

Sodium- Na and the latin name: natrium

Tin- Sn and the latin name: stannum

~~~Inuola1234

8 0

3 years ago

What entropy change is associated with the reversible phase change from 1.0kg of ice to water at 0 ° C?

avanturin [10]

Answer:

1200 J/K

Explanation:

The formula for the entropy associated with a reversible phase change is

$\Delta S= \dfrac{q_{\text{rev}}}{T}$

1. Calculate q

For a reversible phase change like melting,

$q_{\text{rev}} = m\Delta_{\text{fus}}H = \text{1000 g} \times \dfrac{\text{334 J}}{\text{1 g}} = \text{334 000 J}$

2. Calculate ΔS

$\Delta S = \dfrac{q_{\text{rev}}}{T} =\dfrac{\text{334 000 J}}{\text{273.15 K}} = \textbf{1200 J/K}$

3 0

3 years ago