Answer:
The empirical formula is C3H4O4
Explanation:
Step 1: Data given
Suppose we have 100 grams of malonic acid
Malonic acid contains:
34.63 % C = 34.63 grams C
3.87 % H = 3.87 grams H
61.50 % O = 61.50 grams O
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 34.63 grams / 12.01 g/mol
Moles C = 2.883 moles
Moles H = 3.87 grams / 1.01 g/mol
Moles H = 3.83 moles
Moles O = 61.50 grams / 16.00 g/mol
Moles O = 3.844 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 2.883 / 2.883 = 1
H: 3.83/ 2.883 = 1.33
O: 3.844 / 2.883 = 1.33
The empirical formula is C3H4O4
Hello.
The answer is
<span> C. viscosity.
</span>Temperature and silica content determine the viscosity of magma.
The viscosity of amagma<span> is largely controlled by the </span>temperature.
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Have a nice day.</span>
Answer:
Hello my friend! The correct answer to this quastion is "B. carbon + oxygen → carbon dioxide"
Explanation:
Carbon uses oxygen and heat as fuel for the O2 chemical bond breakdown reaction, and the new reaction between carbon and formed oxygen or carbon dioxide.
C + O2 ----> CO2
Hey there!
Molar mass ( NH4)2SO4 = 132.1395 g/mol
So:
1 mole ( NH4)2SO4 ---------------- 132.1395 g
moles (NH4)2SO4 ----------------- 3.30 g
moles (NH4)2SO4 = 3.30 * 1 / 132.1395
moles (NH4)2SO4 = 3.30 / 132.1395
=> 0.0250 moles of (NH4)2SO4
Answer A
Hope that helps!
We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>
