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VashaNatasha [74]
3 years ago
15

Anybody Know This. ?

Mathematics
1 answer:
noname [10]3 years ago
4 0

Answer:

Nope

Step-by-step explanation:

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The temperature fell from 0°F to 6 3/5°F below 0°F in 2 1/5 hours. What was the temperature change per hour.
kakasveta [241]

Answer With Step-by-step explanation:

C: 3

This is because 6 3/5 is a positive number, and 6 3/5 ÷ 2 1/5 = 3

Hope this was helpful! (brainliest please)

6 0
3 years ago
How to erite a sequence of 1/4 , 1/2,3 write a rule for the sequence 1/4 1/2 3/4
FrozenT [24]
The equation for finding the equation of an arithmetic sequence is an=a1+(n-1)d, where n is the input for the sequence, a1 is the first term, and d is the difference between each term. 

a1= 1/4
d= 1/4 

an= 1/4 + (n-1)(1/2) - First you need to distribute the 1/2 to both the n and -1 to get:    an= 1/4 + 1/2n -1/2.

Then you need to add like terms (1/4-1/2) to get an=1/2n-1/4.  Hope this helps!
3 0
3 years ago
A farmer plants apple, pear and cherry trees
gogolik [260]
? is there any more context to the question?
8 0
3 years ago
Write your answer as an integer or as a decimal rounded to the nearest tenth
Gelneren [198K]

Answer:

VW ≈ 4.0

Step-by-step explanation:

Using the sine ratio in the right triangle

sin35° = \frac{opposite}{hypotenuse} = \frac{VW}{VX} = \frac{VW}{7} ( multiply both sides by 7 )

7 × sin35° = VW , then

VW ≈ 4.0 ( to the nearest tenth )

6 0
3 years ago
The following table relates the weights and
MA_775_DIABLO [31]

The probability of randomly chosen tall and obese individuals is 0.30.

Firstly complete the given table and find the total of each row and column.

                 Tall   Medium   Short   Total

Obese             18       28      14  60

Normal           20       51     28         99

Underweight   12       25       9  46

Total          50        104     51 205

We have to find P(Tall | Obese).

P(Tall | Obese) =  P(Tall and Obese) / P(Obese)

Now, P(Tall and Obese) = 18 ÷ 205

And, P(Obese) = 60÷205

Substituting the above values,

P(Tall | Obese) =  18÷205/ 60÷205

P(Tall | Obese) = 18/60

P(Tall | Obese) = 0.30

Hence the probability of a tall and obese individual is 0.30.

To learn more about probability, visit: brainly.com/question/11234923

#SPJ9

8 0
1 year ago
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