Balanced reaction for formation of water is ; 2H2 + O2 —> 2H2O Stoichiometry of H2 to H20 is 2:2 1 mol of any gas occupies a volume of 22.4 L Therefore it 22.4 L contains 1 mole Then 1.24 L has -1/22.4 x 1.24 = 0.055 mol Number of water moles formed = 0.055 mol Therefore mass of water formed = 0.055 mol x 18 g/mol = 0.99 g of water is formed
