The substances which allow the current to flow in the circuit are:
Lithium bromide in a solution and Graphite.
Lithium bromide can be pass the current in the circuit, due to the ability to form ions in the solution Li⁺ and Br⁻ which are mobile and can transport the electrical charge.
In the graphite because of the presence of delocalised electrons, each carbon atom forms three covalent bonds with three other carbon atoms, it conducts electrical current.
In the case of potassium chloride lattice there are in a solid form and the atoms are not mobile so they can not form ions. In the diamond all the carbon valences are satisfied so the electrical charge can not be transported.
Nitric oxide in a solution is isolated and can not transport the electrical current due to its inability of the to form ions
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For the given 200 g of 95% ethanol solution, ethanol is 190g and water is 10g. We determine the number of moles per component.
ethanol: (190 g ethanol) / (46 g/mole) = 4.13 moles
water: (10 g water)/(18 g/mole) = 0.55 moles
Total moles of the solution is 4.68 moles
Mole fraction of water: = 0.55 moles/4.68 moles = 0.117
CO2: 12.0107 + 15.9994(2) = 44
NH3: 14.0067 + 1 (3) = 17
1.55 (17/44) = .599g
Answer:
+6
Explanation:
We are given;
We are required to determine the oxidation number of S in the compound.
We need to know that;
- The total oxidation number of this compound is Zero
- Oxidation number of Ba metal is +2
- Oxidation number of Oxygen atom is -2
- There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.
Therefore; assuming oxidation number of S is x
Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0
2 + x - 8 = 0
x = 6 or +6
Thus oxidation number of Sulfur in BaSO₄ is +6.
