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frutty [35]
2 years ago
9

80. When water forms ice, hydrogen bonds around a water molecules are at ... apart.

Chemistry
1 answer:
Alexxx [7]2 years ago
3 0

Answer:

6

Explanation:i dont know

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Write the answer in scientific notation when you multiply 2 x 104 by 3 x 104.
emmasim [6.3K]

Answer:

6× 10⁸

Explanation:

We need to find the multiplication of 2 x 10⁴ by 3 x 10⁴.

2 x 10⁴ × 3 x 10⁴

= (3 × 2) x 10⁴ x 10⁴

= 6 x 10⁴ x 10⁴

= 6 × 10⁴⁺⁴

= 6× 10⁸

Hence, the required answer is 6× 10⁸.

7 0
3 years ago
What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
____ [38]

E

θ

Cell

=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

2

+

/

Ni

Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

2

l

e

−

→

Mg

(

s

)

−

E

θ

=

−

2.372

l

V

Ni

2

+

(

a

q

)

+

2

l

e

−

→

Ni

(

s

)

−

E

θ

=

−

0.257

l

V

The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

5 0
2 years ago
Read 2 more answers
What type of physical change is it when a liquid turns into a solid and a solid turns into a liquid
goblinko [34]

Answer:

Freezing and Melting (Fusion)

Explanation:

4 0
3 years ago
How do the atomic number and the mass number of an element
Doss [256]

Answer:

A.

Explanation:

3 0
2 years ago
How many milliliters of water will it take to fill a 2 L bottle that already contains 1.87 L of water?
Aloiza [94]

Answer:

0.00013

Explanation:

I'm pretty sure. I first subtracted 1.87 from 2. I got 0.13. The conversion from mL to L is 0.001. I multiplied 0.13 and 0.001 and got <u>0.00013 mL.</u>

6 0
3 years ago
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