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VLD [36.1K]
3 years ago
15

If 0.640 g of beautiful blue crystals of azulene is dissolve in 99 g of benzen, the resulting solutions boils at 80.23 degrees c

elsius. find the molecular formula?
Chemistry
1 answer:
devlian [24]3 years ago
6 0

This problem handles<em> boiling-point elevation</em>, which means we will use the formula:

ΔT = Kb * m

Where ΔT is the difference of Temperature between boiling points of the solution and the pure solvent (Tsolution - Tsolvent). Kb is the ebullioscopic constant of the solvent (2.64 for benzene), and m is the molality of the solution.

Knowing that benzene's boiling point is 80.1°C, we <u>solve for m</u>:

Tsolution - Tsolvent = Kb * m

80.23 - 80.1 = 2.64 * m

m = 0.049 m

We use the definition of molality to <u>calculate the moles of azulene</u>:

0.049 m = Xmoles azulene / 0.099 kgBenzene

Xmoles azulene = 4.87 x10⁻³ moles azulene

We use the mass and the moles of azulene to<u> calculate its molecular weight</u>:

0.640 g / 4.875 x10⁻³ mol = 130.28 g/mol

<em>A molecular formula that would fulfill that molecular weight</em> is C₁₀H₁₀. So that's the result of solving this problem.

The actual molecular formula of azulene is C₁₀H₈.

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if only 0.264 g of ca(oh)2 dissolves in enough water to give 0.178 l of aqueous solution at a given temperature, what is the ksp
Maurinko [17]

The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.

<h3>What is ksp?</h3>

Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.

Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water

The solution equilibrium is

Ca(OH)² = Ca + 2OH

The molar solubility is

0.186 / 74.00  / 0.230 = 0.0109 M

The ksp value will be

Ksp = (s) (2S)²

Putting the values in the formula

(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.

Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.

To learn more about ksp value, refer to the link:

brainly.com/question/27132799

#SPJ4

8 0
1 year ago
How many grams of fluorine must be reacted with excess lithium iodide to produce 10.0 grams of lithium fluoride?
rewona [7]
Answer:
             7.32 g of F₂

Solution:
              The equation is as follow,

                                   2 LiI  +  F₂    →    2 LiF  +  I₂

According to equation,

           51.88 g (2 mole) of LiF is produced from  =  37.99 g (1 mole) F₂
So,
                          10 g of LiF will be produced by  =  X g of F₂

Solving for X,
                      X  =  (10 g × 37.99 g) ÷ 51.88 g

                      X  =  7.32 g of F₂
8 0
3 years ago
The diagram shows a carrier wave before and after modulation. The diagram best represents which type of modulation? FM phase AM
bixtya [17]

Answer: On Edge it's A. FM            

5 0
3 years ago
Read 2 more answers
Consider n2 (g) + 3h2 (g) →→ 2nh3 (g). what is the mass of nitrogen gas required to react with 0.129 g h2?
Flura [38]
The given chemical reaction given above is already balanced such that the number of atoms in the left hand side of the equation is equal to that of the right hand side. Using the dimensional analysis, proper conversion factors and the molar masses,

                    mass of nitrogen = (0.129 g H₂)(1 mol H₂/2 g H₂)(1 mol N₂/3 mol H₂)(28 g N₂/1 mol N₂)
                     mass of nitrogen = 0.602 g N₂

Therefore, 0.602 g of nitrogen will be required for he reaction. 
6 0
3 years ago
Select all of the items that are true about a sample of water vapor at 101°C as it cools.
zloy xaker [14]

Answer:

D. Its temperature will remain 100 C until all the vapours condenses

Explanation:

Heat absorbed by a substance to change the state of matter is known as latent heat. This heat is utilized to break the bonds between atoms of the substance so that they can undergo phase change.

So, when water boils at 100 degree Celsius then temperature will remain constant unless and until all the water changes into vapor. As it is the latent heat that breaks the bonds between hydrogen and oxygen atoms of water so that liquid state can change into gaseous state.

Since latent heat is a hidden heat, that is why, it does not get reflected and there is no change in temperature due to it.

Thus, we can conclude that it is true that temperature will remain at 100°C until all the vapor condenses for a sample of water vapor at 101°C as it cools.

5 0
3 years ago
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