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Anna71 [15]
3 years ago
9

Mountaineer excavation operates in a low-lying area that is subject to heavy rains and flooding. because of this, mountaineer pu

rchases one year of flood insurance in advance on march 1, paying $36,000 ($3,000/month).
Required:
1. Recore the purchase of insurance in advance on March,1.
1. Record the adjusting entry on December, 31.
Business
1 answer:
nordsb [41]3 years ago
5 0

Answer:

1. Recore the purchase of insurance in advance on March,1.

Debit Prepaid Insurance $36,000

Credit Cash $36,000

2. Record the adjusting entry on December, 31.

Debit Insurance Expense $30,000

Credits Prepaid Insurance $30,000

Explanation:

Mountaineer excavation purchases one year of flood insurance in advance on March 1, paying $36,000 ($3,000/month). The company records the insurance as the prepaid Insurance:

Debit Prepaid Insurance $36,000

Credit Cash $36,000

On December, 31, the last day of the following 10 months, the company records an adjusting entry that Credits Prepaid Insurance for $30,000 ($3,000/month times the 10 months) and Debits Insurance Expense for $30,000

Debit Insurance Expense $30,000

Credits Prepaid Insurance $30,000

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Having just one typo on your resume can eliminate you from a job pool
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Identifying time lags Advocates of active policy face several obstacles when implementing discretionary fiscal or monetary polic
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4 0
3 years ago
You're trying to save to buy a new $230,000 Ferrari. You have $32,000 today that can be invested at your bank. The bank pays 5.5
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Answer:

37 years

Explanation:

We know,

Future value = Present value (1 + r)^n

Given,

Future value, FV = $230,000;

Present value, PV = $32,000;

Interest rate, r = 5.5% = 0.055;

We have to determine how many years later I can purchase the Ferrari.

Now, putting the values into the formula, we get,

FV = PV × (1 + r)^n

or, $230,000 = $32,000 × (1 + 0.055)^n

or, $230,000 ÷ $32,000 = (1 + 0.055)^n

or, 7.1875 = (1 + 0.055)^n

or, log 7.1875 = n × log 1.055

or, n × log 1.055 = log 7.1875 [Changing the side]

or, n = log 7.1875 ÷ log 1.055

Using financial calculator/Scientific Calculator,

or, n = 0.8566 ÷ 0.0233

Therefore, n = 36.76 or almost 37 years.

4 0
3 years ago
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