
can be changed into this equation:

The 32 and 8 have a common factor of 8 and can be simplified to become this equation:

Now multiply across to get

which then simplifies to

which as a decimal is 41.333 (repeating 3s). Nearest whole number is 41.
Your answer is
41
Answer: at lease 8 packages of Aero flight tees.
Step-by-step explanation:
At least 10 golf tees for each member of his foursome = total of at least 4*10 = 40 tees.
2 packages of the generic golf tees, that are packaged by the dozen = 2*12 = 24 tees.
So, Bill must buy at least 16 Aero tees.
This means he must buy 8 pairs
Answer:
a2=12 (the second term of the sequence is 12)
Step-by-step explanation:
a5=324
If the term to term rule is multiply by any number, we deal with geometrical sequence
The formula you should use is an= a1*r^(n-1) where n is the number of the term which we know. In our case we know
a5, so use 5 instead of n
Then you have a5=a1*r^4 where r is the number 3 (because each next term is greater than previous in 3 times)
a5=324
324= a1*3^4
324=a1*81
a1=4 (We find the first term of sequence, because having it you can easily search for every term )
Return to the formula an= a1*r^n-1
Now search for the second term using 2 instead of n in the formula
a2= a1*r^1
a2=a1*r, a1=4, r=3
a2=4*3=12
Answer:
The value of the quantity after 87 months will be of 599.64.
Step-by-step explanation:
A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.
This means that the quantity, after t periods of 6 years, is given by:

What is the value of the quantity after 87 months, to the nearest hundredth?
6 years = 6*12 = 72 months
So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).


The value of the quantity after 87 months will be of 599.64.
Answer:
The percentage of students who scored below 620 is 93.32%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Percentage of students who scored below 620:
This is the pvalue of Z when X = 620. So



has a pvalue of 0.9332
The percentage of students who scored below 620 is 93.32%.