Its 0.001
0.01 x100 = 1mm
0.001x100=0.1mm
0.1=10mm
1m
Answer:
500 N
Explanation:
Given;
Mass of the car, M = 1000 kg
initial speed of the car, u = 0 m/s
Final speed of the car, v = 60 m/s
Time, t = 1 min = 60 s
Now,
Force, F is given as:
F = Ma
where,
a is the acceleration
From the Newton's equation of motion, we have
v = u + at
on substituting the values, we get
60 = 0 + a × 60
or
a = 1 m/s²
Thus,
Force = 1000 × 1 = 1000 N
now,
this force will be equal to the friction force provided by the rear wheels
let the friction force on a single rear wheel be 'f'
thus,
2f = 1000 N
or
f = 500 N
Answer:
Electrons in atoms can act as our charge carrier, because every electron carries a negative charge. If we can free an electron from an atom and force it to move, we can create electricity.
Answer:
(a) We are asked to compute the Brinell hardness for the given indentation. for HB, where P= 1000 kg, d= 2.3 mm, and D= 10 mm.
Thus, the Brinell hardness is computed as
![=2*1000hg/\pi (10mm)[10mm-\sqrt{(1000^2-(2.3mm)^2} ]](https://tex.z-dn.net/?f=%3D2%2A1000hg%2F%5Cpi%20%2810mm%29%5B10mm-%5Csqrt%7B%281000%5E2-%282.3mm%29%5E2%7D%20%5D)
(b) This part of the problem calls for us to determine the indentation diameter d which will yield a 270 HB when P= 500 kg.
![d=\sqrt{D^2-[D-\frac{2P}{(HB)\pi D} } ]^2\\=\sqrt{(10mm)^2-[10mm-\frac{2*500}{450( \pi10mm)} } ]^2](https://tex.z-dn.net/?f=d%3D%5Csqrt%7BD%5E2-%5BD-%5Cfrac%7B2P%7D%7B%28HB%29%5Cpi%20D%7D%20%7D%20%5D%5E2%5C%5C%3D%5Csqrt%7B%2810mm%29%5E2-%5B10mm-%5Cfrac%7B2%2A500%7D%7B450%28%20%5Cpi10mm%29%7D%20%7D%20%5D%5E2)
