Answer:
The rate of fuel required to drive the air conditioner 
The flow rate of the cold air is 
Explanation:
From this question we are told that
The efficiency is
% = 0.33
Temperature for the hot day is 
Temperature after cooling is 
The input power is 
The rate of fuel required to drive the air conditioner can be mathematically represented as


From the question the air condition is assumed to be half as a Carnot refrigeration unit
This can be Mathematically interpreted in terms of COP(coefficient of performance) as

where
denotes COP and is mathematically represented as

= > 
Where
is the rate of flue being burned for cold air to flow
Now if the COP of a Carnot refrigerator is having this value



Then


Now substituting the value of
to solve for 



The equation for the rate of fuel being burned for the cold air to flow

Making the flow rate of the cold air


