Answer:
The rate of fuel required to drive the air conditioner
The flow rate of the cold air is
Explanation:
From this question we are told that
The efficiency is % = 0.33
Temperature for the hot day is
Temperature after cooling is
The input power is
The rate of fuel required to drive the air conditioner can be mathematically represented as
From the question the air condition is assumed to be half as a Carnot refrigeration unit
This can be Mathematically interpreted in terms of COP(coefficient of performance) as
where denotes COP and is mathematically represented as
= >
Where is the rate of flue being burned for cold air to flow
Now if the COP of a Carnot refrigerator is having this value
Then
Now substituting the value of to solve for
The equation for the rate of fuel being burned for the cold air to flow
Making the flow rate of the cold air