A car engine with a thermal efficiency of 33% drives the air-conditioner unit (a refrigerator) besides powering the car and othe
1 answer:
Answer:
The rate of fuel required to drive the air conditioner
The flow rate of the cold air is
Explanation:
From this question we are told that
The efficiency is % = 0.33
Temperature for the hot day is
Temperature after cooling is
The input power is
The rate of fuel required to drive the air conditioner can be mathematically represented as
From the question the air condition is assumed to be half as a Carnot refrigeration unit
This can be Mathematically interpreted in terms of COP(coefficient of performance) as
where denotes COP and is mathematically represented as
= >
Where is the rate of flue being burned for cold air to flow
Now if the COP of a Carnot refrigerator is having this value
Then
Now substituting the value of to solve for
The equation for the rate of fuel being burned for the cold air to flow
Making the flow rate of the cold air
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Answer:
Hello your question is incomplete attached below is the complete question
Answer : Factor of safety for point A :
i) using MSS
(Fos)MSS = 3.22
ii) using DE
(Fos)DE = 3.27
Factor of safety for point B
i) using MSS
(Fos)MSS = 3.04
ii) using DE
(Fos)DE = 3.604
Explanation:
Factor of safety for point A :
i) using MSS
(Fos)MSS = 3.22
ii) using DE
(Fos)DE = 3.27
Factor of safety for point B
i) using MSS
(Fos)MSS = 3.04
ii) using DE
(Fos)DE = 3.604
Attached below is the detailed solution
Answer:
The code is attached.
Explanation:
I created a string s including 6 colors with spaces in between. Then I converted the string into a list x by using split() method. I used three different methods for removing elements from the list. These methods are remove(), pop() and del.
Then I used methods append(), insert() and extend() for adding elements to the list.
Finally I converted list into a string using join() and adding space in between the elements of the list.
