F14.33 1425,413 that’s the right number
Answer:
Before Tax: $240
After Tax: $259.20
Step-by-step explanation:
If we are trying to find the original price then here:
216/1.08 = 200
This took away the tax now we need to take away the discount:
200 x 1.2 = 240
Before Tax: $240
After Tax: $259.20
Your answer is 15 over four z + 12. Using the distributive property, 3/4 • 5z equals 15/4z, which can't be simplified. Then 3/4 of 16 is 12. If you divide 16 by 4 (the denominator) and then multiply by 3 (the numerator) that yields your answer.
Answer:
a) n = 1037.
b) n = 1026.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of ![1 - \frac{\alpha}{2}](https://tex.z-dn.net/?f=1%20-%20%5Cfrac%7B%5Calpha%7D%7B2%7D)
The margin of error is:
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
(a) Assume that nothing is known about the percentage to be estimated.
We need to find n when M = 0.04.
We dont know the percentage to be estimated, so we use
, which is when we are going to need the largest sample size.
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
![0.04 = 2.575\sqrt{\frac{0.5*0.5}{n}}](https://tex.z-dn.net/?f=0.04%20%3D%202.575%5Csqrt%7B%5Cfrac%7B0.5%2A0.5%7D%7Bn%7D%7D)
![0.04\sqrt{n} = 2.575*0.5](https://tex.z-dn.net/?f=0.04%5Csqrt%7Bn%7D%20%3D%202.575%2A0.5)
![(\sqrt{n}) = \frac{2.575*0.5}{0.04}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%20%3D%20%5Cfrac%7B2.575%2A0.5%7D%7B0.04%7D)
![(\sqrt{n})^{2} = (\frac{2.575*0.5}{0.04})^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%28%5Cfrac%7B2.575%2A0.5%7D%7B0.04%7D%29%5E%7B2%7D)
![n = 1036.03](https://tex.z-dn.net/?f=n%20%3D%201036.03)
Rounding up
n = 1037.
(b) Assume prior studies have shown that about 55% of full-time students earn bachelor's degrees in four years or less.
![\pi = 0.55](https://tex.z-dn.net/?f=%5Cpi%20%3D%200.55)
So
![M = z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
![0.04 = 2.575\sqrt{\frac{0.55*0.45}{n}}](https://tex.z-dn.net/?f=0.04%20%3D%202.575%5Csqrt%7B%5Cfrac%7B0.55%2A0.45%7D%7Bn%7D%7D)
![0.04\sqrt{n} = 2.575*\sqrt{0.55*0.45}](https://tex.z-dn.net/?f=0.04%5Csqrt%7Bn%7D%20%3D%202.575%2A%5Csqrt%7B0.55%2A0.45%7D)
![(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%20%3D%20%5Cfrac%7B2.575%2A%5Csqrt%7B0.55%2A0.45%7D%7D%7B0.04%7D)
![(\sqrt{n})^{2} = (\frac{2.575*\sqrt{0.55*0.45}}{0.04})^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%28%5Cfrac%7B2.575%2A%5Csqrt%7B0.55%2A0.45%7D%7D%7B0.04%7D%29%5E%7B2%7D)
![n = 1025.7](https://tex.z-dn.net/?f=n%20%3D%201025.7)
Rounding up
n = 1026.
1345/99 = 13.585858
14
Rounding is easy, just look at the number in the tenths place. If the number is less than 5 round down and if the number is greater than or equal to 5 round up.