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3 years ago

Find f (1) if f(x) = -3x – 5.

Mathematics

2 answers:

laila [671]3 years ago

8 0

Answer:

$→ \:{ \tt{f(x) = - 3x - 5}}$

• when x is 1;

$→ \: { \tt{f(1) = - 3(1) - 5}} \\ → \: { \tt{f(1) = - 3 - 5}} \\ \\ → \: { \boxed{ \tt{f(1) = - 8}}}$

Strike441 [17]3 years ago

3 0

Answer:

-8

Step-by-step explanation:

f(1)=-3(1)-5=-3-5=-8

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A study of consumer smoking habits includes 193 people in the 18-22 age bracket (60 of whom smoke), 127 people in the 23-30 age

Thepotemich [5.8K]

Total number of people in the sample = 193 + 127 + 96 = 416

Probability of picking 23-30 year old = 92 /416 = 0.2212 ( not including the people who smoke)

Number of people who smoke = 60+35+23 = 118 people

Prob(someone who smokes) = 118/416 = 0.2837

So required probability = 0.2837 + 0.2212 = 0.505 (answer)

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3 years ago

Find the value of x<br> −8(x−6)=32

RUDIKE [14]

Answer:

x = 2

Step-by-step explanation:

-8(x-6) = 32 (distribute)

-8x+48 = 32 (subtract 48 from both sides)

-8x = -16 (divide)

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3 years ago

Read 2 more answers

The volume of a right cylinder is 155.4 ft. 3 The radius is 3 ft. Determine the height of the cylinder.

BigorU [14]

Answer:

The height is approximately 5.4961507

Step-by-step explanation:

The volume of a right cylinder is $v=$ π · r² · h, where r is the radius and h is the height.

We know the radius and volume. We can figure out the height like so:

$v= pi * r^2 * h\\\\\frac{v}{pi * r^2} = \frac{pi * r^2 * h}{pi * r^2}\\\\\frac{v}{pi * r^2} = h$

Now, we just substitute the known values in for their corresponding variables:

$\frac{155.4}{3.1415927 (approx.) * (3)^2} = h\\\\\frac{155.4}{3.1415927 (approx.) * 9} = h\\\\\frac{155.4}{28.2743339 (approx.)} = h\\\\5.4961507 = h$

The height of the cylinder is approximately 5.4961507

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3 years ago

A farmer in China discovers a mammal hide that contains 37% of its original amount of C-14. Find the age of the mammal hide to t

Naya [18.7K]

Answer: 54678 years

Step-by-step explanation:

This can be solved by the following equation:

$N_{t}=N_{o}e^{-\lambda t}$ (1)

Where:

$N_{t}=54\%=0.54$ is the quantity of atoms of carbon-14 left after time $t$

$N_{o}=1$ is the initial quantity of atoms of C-14 in the mammal hide

$\lambda$ is the rate constant for carbon-14 radioactive decay

$t$ is the time elapsed

On the other hand, $\lambda$ has a relation with the half life $h$ of the C-14, which is $5730 years$ :

$\lambda=\frac{ln(2)}{h}=\frac{ln(2)}{5730 years}=1.21(10)^{-4} years^{-1}=0.000121 years^{-1}$ (2)

Substituting (2) in (1):

$0.54=1e^{-(0.000121 years^{-1}) t}$ (3)

Applying natural logarithm on both sides of the equation:

$ln(0.54)=ln(1e^{-(0.000121 years^{-1}) t})$ (4)

$-0.616=-(0.000121 years^{-1}) t$ (5)

Isolating $t$ :

$t=\frac{-0.616}{-0.000121 years^{-1}}$ (6)

$t=54677.68 years \approx 54678 years$ (7) This is the age of the mammal hide

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3 years ago

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andrey2020 [161]

Answer:

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3 years ago