Answer:
.
Explanation:
-Synthesis reactions are reactions that appear when two distinct atoms or molecules engage to structure a specific molecule or compound. Most of the time, when a synthesis response occurs, electricity is launched and the response is exothermic. However, an endothermic consequence is additionally possible.
-A decomposition response starts offevolved from a single substance and produces extra than one substance; that is, it decomposes. One substance as a reactant and greater than one substance as the merchandise is the key attribute of a decomposition reaction. For example, in the decomposition of sodium hydrogen carbonate (also recognized as sodium bicarbonate)
-A single-replacement response (sometimes referred to as a single-displacement reaction) is a chemical response in which one aspect is substituted for every other factor in a compound, producing a new aspect and a new compound as merchandise
-A double-replacement response (sometimes referred to as a double-displacement reaction) takes place when components of two ionic compounds are exchanged, making two new compounds. A attribute of a double-replacement equation is that there are two compounds as reactants and two distinctive compounds as product
-A combustion response happens when a reactant combines with oxygen, many instances from the atmosphere, to produce oxides of all different factors as products; any nitrogen in the reactant is transformed to elemental nitrogen, N2. Many reactants, referred to as fuels, incorporate normally carbon and hydrogen atoms, reacting with oxygen to produce CO2 and H2O
Answer:
Explanation:
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized.
Consider the following reaction:
2AgCl + Zn → 2Ag + ZnCl₂
In this reaction oxidation state of Zn on left side is 0 while on right side +2 so it gets oxidized and oxidation state of Ag on left side is +1 and on right side 0 so it get reduced.
4NH₃ + 3O₂ → 2N₂ + 6H₂O
In this reaction oxidation state of nitrogen on left side is -3 while on right side 0 so it gets oxidized and oxidation state of oxygen on left side is 0 and on right side -2 so it get reduced.
Fe₂O₃ + 2Al → Al₂O₃ + 2Fe
In this reaction oxidation state of iron on left side is +3 while on right side 0 so it gets reduced and oxidation state of Al on left side is 0 and on right side +3 so it get oxidized.
First, we need the balanced equation: H₂ + Cl₂ ---> 2HCl
since not much information is given, I am assuming we are at STP and that 22.4 Liters= 1 mol
1) let's convert the volume to moles using the molar volume of a gas. also we need to convert the cm₃ to mL, then to Liters.
8 cm³ (1 ml/ 1 cm³)(1 L/ 1000 mL) (1 mol/ 22.4 Liters)= 3.6x10⁻⁴ moles of H₂
2) let's use the mole ratio of the balanced equation to convert moles of H₂ to moles of HCl
3.6x10⁻⁴ mol H₂ (2 mol HCl/ 1 mol H₂)= 7.1x10⁻⁴ mol HCl
3) lastly, we convert the moles of HCl to grams using the molar mass.
molar mass of HCl= 1.01 + 35.5= 36.51 g/mol
7.1x10⁻⁴ mol HCl (36.51 g/mol)=<span> 0.026 grams HCl</span>
Answer:
Boiling T° of solution = 100.6
Explanation:
Formula for elevation of boiling point is:
ΔT = Kb . m . i
where ΔT means Boiling T° of solution - Boiling T° of pure solvent
Our solute is a non ionizing compound.
i = 1, because it is a non ionizing compound. i, indicates the ions dissolved in solution.
m = molality (moles of solute dissolved in 1 kg of solvent)
90 g of solvent = 0.09 kg of solvent
We convert mass of solute to moles (by the molar mass):
10 g . 1 mol /92.09 g = 0.108 moles
m = 0.108 mol /0.09 kg = 1.21 m
Let's replace data: Boiling T° of solution - 100°C = 0.51 °C/m . 1.21 m . 1
Boiling T° of solution = 0.51 °C/m . 1.21 m . 1 + 100°C
Boiling T° of solution = 100.6
O they did not
at least thats what my substitute teacher said
