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3 years ago

9

WHAT DID YOU OBSERVE HAPPENED WHEN AN S-WAVE TRAVELED INTO A LIQUID?

1 answer:

alexgriva [62]3 years ago

8 0

It will spread out making the sound travel faster then it usually does in the air(i think) let me know if you need help with anything else

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QUESTION 5<br> Match the symbol with the type of symbiotic relationship it represents

marshall27 [118]

Answer:

A : 1

B : 3

C : 4

D : 2

6 0

3 years ago

Read 2 more answers

Acid strength in a series of h−a molecules increases with increasing size of

-BARSIC- [3]

Hello there!

The statement that Acid strength in a series of H-A molecules increases with increasing size of A is True.

When only the size is involved, increasing the size will increase the Acid strength because as size increases, the H-A bond will become weaker as the atoms will be farther apart. Acid strength is related to the ability to release H⁺ ions and a weaker H-A bond will release H⁺ more easily.

Have a nice day!

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2 years ago

A 25.0 mL aliquot of 0.0680 M EDTA was added to a 59.0 mL solution containing an unknown concentration of V3 . All of the V3 pre

givi [52]

Answer:

$\mathbf{0.02 M}$

Explanation:

$\text{So, from the given question:}$

$\text{EDTA will make complex with}$ $V^{+3}$ $\text{and the remaining EDTA will react with }$ $Ga^{+3}$

$\text{Hence, the total concentration of}$ $V^{+3}$ & $Ga^{+3}$ $\text{will be equivalent to EDTA concentration.}$

$V_{EDTA} = 25 \ mL$

$V_{V^{+3}} = 59.0 \ mL$

$V_{Ga^{+3}} = 13.0 \ mL$

$M_{EDTA} = 0.0680 \ M$

$M_{V^{+3}} = ???(unknown)$

$M_{Ga^{+3}} = 0.0400 \ M$

$V^{+3} + EDTA \to V[EDTA] + EDTA(Excess) \to^{CoA} \ Ga[EDTA] _{complex}$

$M_{EDTA} \times V_{EDTA} = ( V_{V^+3}\times M_{V^{+3}}+ V_{Ga^{+3} }\times M_{Ga^{+3}}})$

$0.0680 \times 25 = (59\times x + 13 \times 0.040) \\ \\ 1.7 = 59x + 0.52\\ \\ 1.7 - 0.52 = 59x \\ \\ 59x = 1.18$

$x = \dfrac{1.18}{59}$

$\mathbf{x =0.02 \ M }$

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3 years ago

Can you subscribe to me on yt my channel is BigBoss Games

Free_Kalibri [48]

Answer:

yes i did really good channel

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3 years ago

Consider the reaction CaCO3(s) --> CaO(s) + CO2(g)

tankabanditka [31]

Answer:

Kc = [CO2], that is to say it is equal to the concentration of CO2

Explanation:

It is a heterogeneous equilibrium since the substances that participate in the reaction are in different phases

In the heterogeneous limestone decomposition reaction:

CaCO3(s) --> CaO(s) + CO2(g)

The equilibrium constants are:

Kc = [CO2(g)]; Kp = PCO2(g); Kc = Kp (R T)^ −(1−0) = Kp (R T)^ −1

The equilibrium situation is not affected by the amount of solid or liquid, as long as these substances are present.

The equilibrium constant is independent of the amounts of solids and liquids in equilibrium.

4 0

2 years ago