Answer: 1,013.32 cal × 4.18 J/cal = 4,235.68 J
Explanation:
1) Data:
Water ⇒ C = 1 cal/g°C
m = 65.8 g
Ti = 31.5°C
Tf = 36.9°C
Heat, Q = ?
2) Formula:
Q = mCΔT
3) Calculations:
Q = 65.8g × 1 cal/g°C × (46.9°C - 31.5°C) = 1,013.2 cal
4) You can convert from calories to Joules using the conversion factor:
1 cal = 4.18 J
⇒ 1,013.32 cal × 4.18 J/cal = 4,235.68 J
7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.
<h3>How to find the number of moles ?</h3>
Number of moles = 
<h3>What is Avogadro's Number ?</h3>
Avogadro's number is the number of particles in one mole of substance. 6.022 × 10²³ is known as Avogadro's Constant / Avogadro's Number.
Avogadro's Number = 6.022 × 10²³
Now put the values in above formula we get
Number of moles =
= 
= 7.32 moles
Thus from the above conclusion we can say that 7.32 moles of Chromium is present in 4.41 × 10²⁴ atoms.
Learn more about the Avogadro's Number here: brainly.com/question/1581342
#SPJ1
Answer:
The group given the sugar pills.
Explanation:
The control group is the ones given sugar pills because they did not get the experimental aspirin
Explanation:
When water vapour changes to liquid water then this process is known as condensation.
For example, when lid is placed in a hot water filled pan then after sometime vapours appear on the surface of lid. When temperature of water decreases then water vapours convert into liquid form.
Thus, we can conclude that in condensation water vapor changes to liquid water.
<u>0.12 atm</u><u> </u><u>vapor pressure</u><u> of ethanol at 45.0 C.</u>
What is vapor pressure in science definition?
- Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.
- The temperature at which the vapour pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid.
We will use the Clausius-Clapeyron equation,
ln(P2/P1) = dHvap/R[1/T1-1/T2]
where,
P1 = unknown
P2 = 1 atm
T1 = 30 oC = 30 + 273 = 303 K
T2 = 78.3 oC = 78.3 + 273 = 351.3 K
dHvap = 39.3 kJ/mol = 39300 J/mol
R = 8.314 J/K.mol
Feed values,
ln(1/P1) = 39300/8.314[1/303 - 1/351.3]
P1 = 0.12 atm
thus, the vapor pressure at 30° C is 0.12 atm.
Learn more about vapor pressure
brainly.com/question/2510654
#SPJ4
