Ask question

Ask question

All categories

3 years ago

8

2. In the water cycle, lake water will do which

1 answer:

aalyn [17]3 years ago

6 0

Water is always on the move. Rain falling today may have been water in a distant ocean days before. And the water you see in a river or stream may have been snow on a high mountaintop. Water is in the atmosphere, on the land, in the ocean, and underground. It moves from place to place through the water cycle.

Where's the water?

There are about 1.4 billion km3 of water (336 million mi3 of water) on Earth. That includes liquid water in the ocean, lakes, and rivers. It includes frozen water in snow, ice, and glaciers, and water that’s underground in soils and rocks. It includes the water that’s in the atmosphere as clouds and vapor.

If you could put all that water together – like a gigantic water drop – it would be 1,500 kilometers (930 miles) across.

You might be interested in

In the conclusion to the snake mole lab, you have to convert 3.45 moles of (NH4)2S04 to

Serhud [2]

Molar mass = 132.14g/mol

3 0

3 years ago

Pls help ASAP I DONT have time IT ALSO DETECTS IF ITS RIGHT OR WRONGG ......just answer the bottom one not the top plss

Iteru [2.4K]

Answer:

a microhabitat is a habitat which is of small or limited extent .

Explanation:

3 0

3 years ago

One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate

Ugo [173]

Answer:

$\delta H_{rxn} = -66.0 \ kJ/mole$

Explanation:

Given that:

$3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \ \ \delta H = -47.0 \ kJ/mole -- equation (1) \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)} \ \ \delta H = -25.0 \ kJ/mole -- equation (2) \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole -- equation (3)$

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

$3FeO_{(s)} + CO_{2(g)} \to Fe_3O_4_{(s)} + CO_{(g)} \ \delta H = -19.0 \ kJ/mole -- equation (4)$

Multiplying (2) with equation (4) ; we have:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

From equation (1) ; multiplying (-1) with equation (1); we have:

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

From equation (2); multiplying (3) with equation (2); we have:

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

Now; Adding up equation (5), (6) & (7) ; we get:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

<u> </u>

$FeO \ \ \ + \ \ \ CO \ \ \to \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \ \delta H = - 66.0 \ kJ/mole$

<u> </u>

<u />

$\delta H_{rxn} = \delta H_1 + \delta H_2 + \delta H_3$ (According to Hess Law)

$\delta H_{rxn} = (-38.0 + 47.0 + (-75.0)) \ kJ/mole$

$\delta H_{rxn} = -66.0 \ kJ/mole$

8 0

3 years ago

What is the mass of an object if force of -136 n can make it accelerate at -9.6 m/s^2

vampirchik [111]

The answer for the following problem is mentioned below.

<em><u>Therefore the mass of an object is 14.16 grams.</u></em>

Explanation:

Force:

The push or pull on an object with mass that cause change in the velocity

It is a vector quantity.

The formula to calculate the force is:

F = m × a

Given:

Force (F) = -136 N

acceleration (a) = -9.6 m/s^2

To calculate:

mass of the object (m)

We know that,

<em>F = m × a</em>

where,

F represents the force of the object

m represents mass of an object

a is acceleration of an object

From the equation;

-136 = m × -9.6

m = $\frac{-136}{-9.6}$

m = 14.16 grams

<em><u>Therefore the mass of an object is 14.16 grams.</u></em>

3 0

4 years ago

What's the force between two moving objects that are touching called

m_a_m_a [10]

I think it is friction.

7 0

4 years ago