Answer: Last option
2.27 m/s2
Explanation:
As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.
If we call a_c to the centripetal acceleration then, by definition
in this case we know the speed of the runner
The radius "r" will be the distance from the runner to the center of the track
The answer is the last option
Do you have a picture then I could determine 1 millimeter
The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
<h3>Velocity of the object at the end of the time</h3>
F = mv/t
where;
- m is mass of the object
- v is velocity of the object
- t is time
Ft = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
<h3>Distance traveled by the object</h3>
v² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
Learn more about distance here: brainly.com/question/2854969
#SPJ1
The voltage in the resistor is 63 V
Explanation:
We can solve the problem by applying Ohm's law, which states the relationship between voltage, current and resistance in a resistor:
where
V is the voltage
R is the resistance
I is the current
For the resistor in this problem, we have:
I = 0.42 A is the current
is the resistance
Substituting into the equation, we find the voltage needed:
Learn more about voltage and current:
brainly.com/question/4438943
brainly.com/question/10597501
brainly.com/question/12246020
#LearnwithBrainly
The cross section is the little tiny circle you see when you cut a wire
and look at the flat, cut end.
The cross-sectional area of the wire is the area of that little circle.
It's equal to
Area = (pi) x (1/4) x (Diameter of the wire)²
