The potential energy as it reaches a height of 0.63 meters is mgh
Since total mechanical energy is conserved, Set that equal to the initial kinetic energy which is 0.5mv^2
2*9.8*0.63 = 0.5*2*v^2
12.348 = v^2
3.51 = v
That's it's initial speed.
A) We can use the equation of motion:
2as = v² - u²
s = (12² - (-6)²) / 2 x 4
s = 13.5 m
b) We calculate the time over which this displacement occurred using:
v = u + at
t = (12 - -6)/4
t = 4.5 seconds
Assuming the average speed equal to:
(12 + 6) /2 = 9 m/s
average speed = total distance/total time
total distance = 9 x 4.5
= 40.5 m
Answer:
E = 1000 x
Explanation:
The electric potential and the electric field are related by the formula
dV = - E . dx
Bold represents vectors.
The point represents the scalar product, in this case we calculate the electric field in the x-axis and the potential is also in this axis so the scalar product is reduced to the algebraic product
E = dV /dx
Let's make the derivative
E = - 2ax
Let's replace the values
E = -2 (-500) x
E = 1000 x
