Can someone please help me I’m stuck with this question I don’t know what’s the answer please help
1 answer:
<em>Answer:</em>
<h2><em>the </em><em>SSS </em><em>similarity</em><em> </em><em>theorem</em></h2><em>Please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
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El pedazo que esta mas grande es 1/2, inclui una foto para que te pueda ayudar.
The measure of ∠ACB will be 110°
<u><em>Explanation</em></u>
According to the diagram below, and
are the perpendicular bisectors of
and
respectively and they intersect side
at points
and
respectively.
So, and
Now, <u>according to the postulate</u>, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.
That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ
As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ =
°
Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°
Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°
