1,3,5
4 looks like true but decreasing but 2 dollars also gives max revenue, so I not sure about it
Answer:
g(x) = |x+3|-2
Step-by-step explanation:
to move horizontally replace each x with (x ± c)
if you move it to the right, you need x - c
if you move it to the left , you need x + c
so , since we are moving 3 units to the left, we replace the x with x+3
g(x) = |x+3|-2
Answer:
x = 100
Step-by-step explanation:


now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.
so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.
therefore, we settle for the endpoints, 4 and 6,
f(4) =3 and f(6) = 7
doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.