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Sedbober [7]
3 years ago
10

Sarah is baking cookies to put a package is for a Fund raiser. She has made 26 chocolate chip cookies and 42 sugar cookies. She

wants soup three identical packages of cookies to sell and that Matthews our cookifund raiser. She has May 26 chocolate chip cookies and 42 sugar cookies. She wants soup three identical packages of cookies to sell and must use all cookies. What is the greatest number of identical packages that Sarah can make
Mathematics
1 answer:
creativ13 [48]3 years ago
6 0

may i please get brainlyest She can make 42 identical packages which contains 2 chocolate chip cookies and 1 sugar cookies.

86 / 2 = 43 chocolate chips cookies

42 / 1 = 42 sugar cookies

Though the chocolate chip cookies can make 43 packs, the sugar cookies cannot fulfill the extra pack for it only has 42 pieces. That is why the maximum number of package that  has identical content is 42 packages.

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Solve −4(x + 10) − 6 = −3(x − 2). (1 point)
AURORKA [14]

Hey there!!

Given equation :

... -4 ( x + 10 ) - 6 = -3 ( x - 2 )

Using the distributive property :

... -4x - 40 - 6 = -3x + 6

Combining like terms :

... -4x - 46 = -3x + 6

Adding 46 on both sides :

... -4x = -3x + 52

Adding 3x on both sides :

... -x = 52

... x = -52

Hope helps!

8 0
3 years ago
Evaluate 8x6+(12-4) dived by 2
soldi70 [24.7K]

Answer:

52

Step-by-step explanation:

48+8/2

48+4

52

7 0
3 years ago
There are 42 kids on the playground. Then 26 more kids come out to join them. How many kids are now on the playground all togeth
aev [14]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
The figure consists of a quarter circle and a parallelogram. What is the area of the composite figure? Use 3.14 for n 76, Round
asambeis [7]
A is the answer i think
3 0
2 years ago
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