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zloy xaker [14]
3 years ago
15

A graph shows time (minutes), numbered 2 to 18 on the horizontal axis (t), and altitude in feet, numbered 30 to 270 on the verti

cal axis (h). A solid circle appears at point (0, 210) and point (14, 0), and a line connects the 2 points.
What is the domain of the function represented in the graph?

{t| 0 ≤ t ≤ 14}
{h| 0 ≤ h ≤ 210}
{t | 0 ≤ t ≤ 210}
{h | 0 ≤ h ≤ 14}
Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0

Ansnwer

{t| 0 ≤ t ≤ 14}

Step-by-step explanation:

I got it right on edge 2020

Stolb23 [73]3 years ago
5 0

Answer:

A. {t| 0< t < 14}

Step-by-step explanation:

got it right

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True or false: f(x) represents a function.<br> A. True <br> B. False
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Answer:

A.) True

Step-by-step explanation:

A set of outputs and inputs becomes a function when there is only one output per input. In this case, each "x" value only has one "y" value, making it a function.

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2 years ago
Rachel is driving to visit her mother, who lives 250 miles away. How long will the
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Answer:

Time for a round trip = 12.5 hours

Step-by-step explanation:

Mother's house = 250 miles

Total distance for the round trip = 250 + 250 = 500 miles

Given speed = 40 mph

<em><u>Find time .</u></em>

<em><u></u></em>Speed = \frac{distance }{Time }\\\\Time = \frac{distance }{speed } = \frac{500}{40} \\\\Time  = 12.5 \ hours<em><u></u></em>

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3 years ago
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PLEASE HELP!!! Write the expression as a single logarithm.<br> 3 log(4) + log(7)
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3 log(4) + log(7)

We know that a log b = log b^a

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log 64 + log 7

We know that log a + log b = log (a*b)

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At a point on the ground 80 ft from the base of a tree, the distance to the top of the tree is 11 ft more than 2 times the heigh
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Let h be the height of the tree and d the distance to the top of the tree from the point on the ground. Draw a diagram to visualize the situation:

Since the distance to the top of the tree is 11 ft more than two times the height, then:

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Use the Pythagorean Theorem to relate the length of the sides of the right triangle:

\begin{gathered} h^2+80^2=d^2 \\ \Rightarrow h^2+6400=(2h+11)^2 \\ \operatorname{\Rightarrow}h^2+6400=(2h)^2+2(11)(2h)+11^2 \\ \operatorname{\Rightarrow}h^2+6400=4h^2+44h+121 \end{gathered}

Notice that we have obtained a quadratic equation in terms of h. Write it in standard form and use the quadratic formula to solve for h:

\begin{gathered} \Rightarrow0=4h^2+44h+121-h^2-6400 \\ \Rightarrow0=4h^2-h^2+44h+121-6400 \\ \Rightarrow0=3h^2+44h-6279 \\ \Rightarrow3h^2+44h-6279=0 \\  \\ \Rightarrow h=\frac{-44\pm\sqrt{(44)^2-4(3)(-6279)}}{2(3)} \\  \\ \therefore h_1=39 \\ h_2=-53.666.. \end{gathered}

Since the height of the tree must be positive, the only solution is h=39ft. To the nearest foot, the height of the tree is 39.

Therefore, the height of the tree is 39 ft.

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