All categories

2 years ago

Given the function f(x) = 3x + 2, and g(x) = -x + 10, find the value of x for which f(x) = g(x).

Mathematics

1 answer:

Fantom [35]2 years ago

7 0

Answer:2 I thinkkk

Step-by-step explanation:

You might be interested in

5 metric tons = ____ kilograms

ANEK [815]

Answer:

5000

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use what you know about signed numbers to complete these square box problems

morpeh [17]

Answer:

We need to know what the boxes are, you didnt include numbers so we cant help you :) Have a great day and i hope you figure the problem out with the help with our Brainly workers! -Conner

Step-by-step explanation:

6 0

2 years ago

Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]

JulijaS [17]

Answer:

$f_{avg}=\frac{1}{e-1}$

Step-by-step explanation:

We are given that a function

$f(x)=2lnx$

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx$

By Parts integration formula

$\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx$

u=ln x and v=dx

Apply by parts integration

$f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))$

$f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})$

$f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}$

By using property lne=1,ln 1=0

$f_{avg}=\frac{1}{e-1}$

8 0

2 years ago

Is 2 a solution to the equation 1/2x-4=5?

dusya [7]

9514 1404 393

Answer:

Step-by-step explanation:

Put 2 where x is and see if you get a true statement.

1/2(2) -4 = 5

1 -4 = 5

-3 = 5 . . . . . . False

2 is not a solution to the equation.

The solution is x=18.

6 0

2 years ago

Write three different ways for7/10

HACTEHA [7]

The only ways i thought of was 0.7, 0.70, and 0.700 .

7 0

3 years ago

Read 2 more answers