FG : (3,7)(-4,-5)
slope = (-5 - 7) / (-4-3) = -12/-7 = 12/7
y = mx + b
slope(m) = 12/7
(3,7)...x = 3 and y = 7
now we sub, we r looking for b, the y int
7 = 12/7(3) + b
7 = 36/7 + b
7- 36/7 = b
49/7 - 36/7 = b
13/7 = b
so ur equation is : y = 12/7 + 13/7.....slope = 12/7, y int = 13/7
HI : (-1,0)(4,6)
slope = (6 - 0) / (4 - (-1) = 6/5
no need to go any farther.....these lines have different slopes...and their not negative reciprocals....so there will be one solution. Answer is : neither.
Answer:
48.8 lbs
Step-by-step explanation:
The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:
a/sin(A) = c/sin(C)
x/sin(26°) = 80/sin(134°)
x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds
The larger component force is about 48.8 pounds.
I-1 is the polynomials because I is the linear term and 1 is the constant
Answer:
no solution.
Step-by-step explanation:
1) in order to explain, the given system should be resolved:

2) the both equations have the same slope (it is 3), it means the given lines are parallel, then no solution.
Hopes this help:
Answer: x = 3, -2 & y = 5, 0
Hopes this is the answer that you where looking for if not I am so sorry.