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g100num [7]
2 years ago
5

Draw a figure in the coordinate plane with at least three of following properties: 6 vertices 1 pair of parallel sides At least

1 right angle 2 sides with the same length. Is this figure a polygon? Explain how you know.
Mathematics
2 answers:
loris [4]2 years ago
5 0

Answer:

Step-by-step explanation:

you have to draw it

dem82 [27]2 years ago
4 0

Answer: draw it out

Step-by-step explanation:

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Juan brought 4 Tshirts and leather jacket. The T shirts were all the same price, and the price of the leather jacket was 6 times
Alex

Let us say that:

x = the number of T shirts bought = 4

y = the number of leather jackets bought = 1

a = the price of the T shirts

b = the price of the leather jackets

 

With the given variables, we can say that the total cost is:

total cost = a x + b y

 

Since, b = 6 a, therefore:

total cost = a x + 6 a y

total cost = a (x + 6 y)

 

Since total cost is 209, therefore we can calculate for a since x and y are also given:

209 = a (4 + 6 * 1)

209 = a (10)

a = $20.9

 

<span>Therefore each T shirt cost $20.9</span>

7 0
3 years ago
Eugene earns $17 per hour tutoring athletes at Brooklyn University.
Nezavi [6.7K]

Answer:

A) $204   B) $331.50

Step-by-step explanation:

For both scenarios, you just multiply the amount of hours worked by the amount per hour to find the total amount made.

7 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
3 years ago
Write a function rule that represents each sentence c is 8 more than half of n
Olegator [25]
C= n/2+ 8 this is your answer
6 0
3 years ago
Read 2 more answers
BRCA1 is a gene that has been linked to breast cancer. Researches at Stanford University wanted to estimate what proportion of w
Evgesh-ka [11]

Answer:

The point estimate for the proportion of women with BRCA1 mutation is 0.168

Step-by-step explanation:

The point estimate for the proportion of women with BRCA1 mutation is the number of women with this mutation divided by the size of the sample.

Of the 173, they found that 29 had BRCA1 mutations.

29/173 = 0.168

The point estimate for the proportion of women with BRCA1 mutation is 0.168

7 0
3 years ago
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