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frosja888 [35]
3 years ago
6

Two important checkpoints that regulate the cell's progression through the cell cycle occur in the _____ and _____ phases of the

cell cycle. See section 12.3 (page 264) .
Biology
1 answer:
Galina-37 [17]3 years ago
6 0

Two important checkpoints that regulate the cell's progression through the cell cycle occur in the G1 and G2 phases of the cell cycle.

G1 (restriction) checkpoint  - the cell becomes committed to entering the cell cycle

G2 checkpoint - chromosomes have replicated successfully.


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One of the traits that we looked at in class was a widow's peak (has peak is dominant, no peak is recessive). For each individua
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Explanation: 1) Individual who is bald but neither parents has a widow's peak: As having a peak is dominant and the individual is bald with parents that doesn't have the trait, the genotype is recessive, in the case ww;

2) Individual has a widow's peak: The individual's genotype can be WW, homozygous for the trait or Ww, heterozygous for the trait, depending on the genotype of the parents;

3) Individual can't roll their tongue: Being able to roll the tongue is a dominant characteristics, so if the individual can't roll their tongue means the genotype is recessive. But, there is little evidence that this trait is dominant or inheritable;

4) Individual has a widow's peak  but their mother does not: In this case, the genotype of the individual is heterozygous (Ww), because the mother is recessive (ww) and the offspring has the trait, so the father must have had it;

5) If an individual does not have a widow's peak (ww), which genotype would be impossible? If this individual crosses over with another individual with the same trait, their children will be all recessive for widow's peak (ww), so there is no possibility of an offspring with the trait;

If the initial individual crosses over with an individual with widow's peak, two possiblities can occur:

  • If the crossover is with an individual homozygous for the trait (WW): all their children will have widow's peak with genotype Ww. So, the possibility of not having the peak is 0;
  • If the crossover is with an individual heterozygous for the trait (Ww), there will be a probability of 25% for the children to have genotype WW, a probability of 50% for the offspring to be heterozygous (Ww) and has the trait and probability of 25% to be recessive (ww) and therefore doesn't have the trait;

8 0
3 years ago
Assume that in squashes the difference in fruit weight between a 3-lb type and a 6-lb type results from three independently segr
3241004551 [841]

Answer:

F1: Aa Bb Cc: 4.5 lbs

F2: Too many to list: Between 3 lbs and 6 lbs

Explanation:

F1: Aa Bb Cc, will be the genotypes and will weigh 4.5 lbs, the reason for that is because each capital letter allele adds half a pound to the base weight of 3 lbs.

F2: There are many different genotypes that can be present in the second generation, for example (AA BB CC, AA BB Cc, AA BB cc, etc.) each of which will allow the plant to grow to a certain height. The majority of phenotypes will be 4.5 lbs. There will be one who is AA BB CC, and another one person who has the code, aa bb cc.

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