At this point in the story, Beasy has driven his car (2+6+4) = 12 km.
He is parked at the thrift store, (2+4) = 6 km East and 6 km North of his starting point.
As the crow flies, the thrift store is √(6km² + 6km²) in a straight line from the starting point.
That's √(72 km²) , which works out to 8.485 km . When rounded to the nearest whole km, he can phone up his wife and tell her he's "eight kilometers from home can you hear me now ?".
Displacement is a vector, so to answer the question completely, we also need to state its direction.
The angle from home to the thrift store, relative to East, is arctan(6km/6km).
That's 45 degrees.
The full displacement vector is <em>8.485 km Northeast.</em>
False
-A magnet can never have one pole, even a simple magnet was cut, each end would have an opposite south(-) or north(+) pull.
-This is the result of moving electrons
The highest point of the wheel is the position of the wheel when its potential energy is greatest.
<h3>At what position of the wheel potential energy is greatest?</h3>
The position of the wheel when its potential energy is greatest when it is at the highest point because potential energy depends on the height of an object. If the object is at more height then it has more potential energy and vice versa.
So we can conclude that the highest point of the wheel is the position of the wheel when its potential energy is greatest.
Learn more about energy here: brainly.com/question/13881533
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Answer:
204kW
Explanation:
P = t x ω = 500 x (2πx3900/60) = 204203W = 204kW
This Question is not complete
Complete Question:
a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.
Answer in units of m/s2
b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under
these new conditions.
Answer in units of m/s2
Answer:
a. 2.875m/s²
b. 3.172m/s²
Explanation:
a. The formula for centripetal acceleration = (speed²) ÷ radius
Centripetal acceleration = (5.7m/s)²÷ 11.3m
Centripetal acceleration = 2.875m/s²
b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.
Centripetal acceleration ( acceleration x) = 2.875m/s²
Increase in the speed rate ( acceleration n) = 1.34m/s²
Magnitude of acceleration = √a²ₓ + a²ₙ
=√( 2.875m/s²)²+ (1.34m/s²)²
= √ 10.06m/s²
= 3.172m/s²
