The answer is struggling to perform
Longggggg duhhhhhh !!!!!!!!
Answer:
+ 0.07 C
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
The energy (E) , potential difference (V) and charge (Q) are related by the following equation:
E = ½QV
With the above formula, we can obtain the charge as follow:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
E = ½QV
0.418 = ½ × Q × 12
0.418 = Q × 6
Divide both side by 6
Q = 0.418 / 6
Q = + 0.07 C
Answer:
r = 50[m]
Explanation:
Since the instrument has an operating or range radius, we must calculate this working distance or radius. We can determine the working area with the values that were given to us.
Now using the area of the circle we can find the radius.
Weight = mg Mass, m = 8kg, g ≈ 9.8 m/s² on Earth
W = 8*9.8
W ≈ 78.4 N