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2 years ago

Gravity can be described as (2 points)

Physics

1 answer:

ladessa [460]2 years ago

6 0

Answer:

"the force of attraction between two objects"

Explanation:

According to Newton's Universal Law of Gravitation, gravity is a force of attraction acting between objects that possess mass. The fact that we only observe gravitational attraction (as opposed to repulsion) makes gravity unique among the known forces.

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a 25 newton force applied on an object moves it 50 meters. the angle between the force and displacement is 40.0°. what is the va

LiRa [457]

Work = force × distance × cos(angle)

work = (25)(50)(cos (40))

work = 957.56 Joules

= 9.6x10^2 Joules

3 0

3 years ago

Two ice skaters push off against one another starting from a stationary position. The 54.1-kg skater acquires a speed of 0.375 m

asambeis [7]

Answer:

0.338125 m/s

Explanation:

Applying,

Law of conservation of momentum

m'v' = mv............ Equation 1

Where m' = mass of the first skater, v' = velocity of the first skater, m = mass of the second skater, v = velocity of the second skater.

make v the subject of the equation

v = m'v'/m........... Equation 2

From the question,

Given: m' = 54.1 kg, v' = 0.375 m/s, m = 60 kg

Substitute these values into equation

v = (54.1×0.375)/60

v = 20.2875/60

v = 0.338125 m/s

3 0

2 years ago

Charges of +5C and −9C are at a distance of 1m from each other. Which diagram represents the force between the two charges?

weqwewe [10]

the answer is CCCCCCCCCCCCCCCCC

8 0

3 years ago

Read 2 more answers

In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu

tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

$294.3sin\theta = 20$

$sin\theta = 20/294.3 = 0.068$

$\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0$

So the ramp cannot be larger than 3.9 degrees

6 0

3 years ago

A trip is taken that passes through the following points in order

AURORKA [14]

Answer:

15? I actually don't know

3 0

3 years ago