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3 years ago

11

Gravity can be described as (2 points)

1 answer:

ladessa [460]3 years ago

6 0

Answer:

"the force of attraction between two objects"

Explanation:

According to Newton's Universal Law of Gravitation, gravity is a force of attraction acting between objects that possess mass. The fact that we only observe gravitational attraction (as opposed to repulsion) makes gravity unique among the known forces.

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A 5.0 kg wooden block Is 100 meters from the ground. What is the gravitational potential energy for the block?

iren [92.7K]

Answer:

<h2>4900 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 5 × 9.8 × 100

We have the final answer as

<h3>4900 J</h3>

Hope this helps you

7 0

3 years ago

What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach

Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$I(\tau)=0.051 A$

b

$I(3 \tau)=0.076 A$

c

$I_c= 0.08 A$

Explanation:

From the question we are told that

$I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R$

From the question we are told to find $I(\tau)$ when t=0 equals the time constant ( $\tau$ )

That is to obtain $I(\tau)$ .This is mathematically represented as

$I(\tau = t) = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })$

Substituting 12 V for $\epsilon$ and 150Ω for R

$I(\tau) = \frac{12}{150} (1- e^{-1})$

$=0.051 A$

From the question we are told to find $I(3 \tau)$ when t=0 equals the 3 times the time constant ( $\tau$ )

That is to obtain $I(3\tau)$ .This is mathematically represented as

$I(\tau = t) = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })$

$I(\tau) = \frac{12}{150} (1- e^{-3})$

$=0.076 A$

As tends to infinity $\frac{\infty}{\tau} = \infty$

So $I_c$ would be mathematically evaluated as

$I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})$

$= \frac{12}{150}$

$= 0.08 A$

5 0

3 years ago

A 10.0 kilogram mass of iron on earth exerts a downward force of 98 Newtons. On the moon this same 10.0 kilograms of iron is wei

Len [333]

Answer: D) The gravity on the moon is one sixth the gravity of Earth.

Explanation:

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Hey if your answering this can you just answer the number 14 I already got the rest<br> thanks

Scrat [10]

Layer a is the answer

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2 years ago

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Rock composed of many thin layers. This image appears in an Earth science magazine with this caption: "A non-foliated rock found

blondinia [14]

Answer:

its B

Explanation:

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3 years ago

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