The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.
The given parameters;
- time of fall of the first ball, t = 1 s
- time of fall of the second ball, t = 3 s
The distance traveled by each ball is calculated using the second equation of motion as shown below.
The distance traveled by the first ball is calculated as follows;

The distance traveled by the second ball is calculated as follows;

Thus, the second ball traveled a greater distance because it spent more time in motion.
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Answer: The correct answer is option b.
Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.
The acceleration of the rocket is 
To calculate the distance of rocket, we use third equation of motion, which is:

where, v = final velocity = 445m/s
u = initial velocity = 0m/s
a = acceleration = 
s = distance = ? m
Putting values in above equation, we get:

The farther the distance, the weaker the gravitational force
Answer:
i have to say whether its correct or wrong yep