K.E=0.5*mv²
v=square root 2ke/m
v= square root 2*8J/1 kg
v= 4 m/s
Answer:
336.9520 atm
Explanation:
The Gas Equation is as follows;-
Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)
Given Parameters
Number of moles-0.614 mol
Temperature 12°C or 12+273.15 ie 285.15°F
Volume-4.32 L
Universal Gas Constant-8.314 J/mol·K
Pressure -?(in atm)
Plugging in all the values in the Gas Equation:-
Pressure=
Pressure=336.9520 atm
Answer:
In Step 5, you will calculate H+/OH– ratios for more extreme pH solutions. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 2. Then divide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C.
What is the concentration of H+ ions at a pH = 2?
0.01 mol/L
What is the concentration of OH– ions at a pH = 2?
0.000000000001 mol/L
What is the ratio of H+ ions to OH– ions at a pH = 2?
10,000,000,000 : 1
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I LITERALLY spent 40 MINUTES trying to figure out this question, so please, use my VERY CORRECT answers!
I hope this helps!
Answer:
b) 7.00
Explanation:
N( t ) = -20( t - 5 )²
dN/ dt = -20 x 2 ( t - 5 )
For maximum N ( depth )
dN/dt = 0
- 40 ( t - 5 ) = 0
t = 5
So at 2 + 5 = 7 .00 am depth of water reaches its maximum.
Answer:
A
Explanation:
A. The pencil is on the table in broad daylight
