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Lyrx [107]
3 years ago
14

An adult African elephant weighs 8.25 tons. How much do 27 elephants weigh?

Mathematics
1 answer:
ohaa [14]3 years ago
6 0

I do believe that you would multiply the number of elephants by how much one weighs on average.. That would mean 8.25x27 which would equal 222.75


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You roll a red die and a green die. What is the size of the sample space of all possible outcomes of rolling these two dice, giv
VladimirAG [237]
(red, green) = (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Size of sample space = 18.
6 0
3 years ago
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

4 0
3 years ago
Help please, I’m not sure
Aleksandr [31]
YOUR ANSWER IS A
HOPE THIS HELPS
5 0
3 years ago
Solve the following <br><br><br> C^2-14=5c
kipiarov [429]

Answer:

c = - 2, c = 7

Step-by-step explanation:

Given

c² - 14 = 5c ( subtract 5c from both sides )

c² - 5c - 14 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the constant term (- 14) which sum to give the coefficient of the c- term (- 5)

The factors are - 7 and + 2, since

- 7 × 2 = - 14 and - 7 + 2 = - 5, hence

(c - 7)(c + 2) = 0

Equate each factor to zero and solve for c

c - 7 = 0 ⇒ c = 7

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8 0
3 years ago
If figure 1 has 4 tiles, fig 2 has 10, and fig 3 has 16... What is my rule?
FinnZ [79.3K]

Answer:

an = 6n -2

Or

an+1 = an +6

Step-by-step explanation:

to go from 4 to 10 we add 6 tiles

to go from 10 to 16 we add 6 tiles

We add 6 tiles each time

an = a1 + d(n-1)  where an is the value of the nth term  a1 is the first term  d is the common factor and n is the term number

an = 4 + 6( n-1)

an = 4 + 6n -6

an = 6n -2

Or

an+1 = an +6

7 0
3 years ago
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