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Marizza181 [45]
3 years ago
11

Katie has a coin collection she keeps 7 of the coing in the box which is only 14% of her entire collection. What is the total nu

mber of coins in katie's collection
Mathematics
2 answers:
Mnenie [13.5K]3 years ago
5 0
14/100x = 7
0.14x = 7
X = 50 coins
mr Goodwill [35]3 years ago
3 0

Answer:

x= 50

Step-by-step explanation:

7/x = 14/100

14x = 700

x = 50

the reason behind my calculations were to get the same ratios and because they gave us percentage and the actual number, we can set them; 14 percent 14/100, however, the 7/x is because we don't know the 100 percent of the coins which is what we look for. Therefore, you cross multiply and get x.

I hope this helped

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If 1 mile is approximately 1610 meters, which is closest to the number of miles in 10,000
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adoni [48]

Answer:  x ≥ 4

<u>Step-by-step explanation:</u>

x + 10 ≥ 14

Subtract 10 from both sides of the equation:

x      ≥ 4

Graphing:

> and < symbols represent an open dot

≥ and ≤ symbols represent a closed dot

Since the solution is: x ≥ 4, we will use a closed dot and the arrow will point to the right of 4.

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4 years ago
Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

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3 years ago
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