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3 years ago

9

a recent survey of 300 pet owners that have either cats or dogs reveals that two thirds are dog owners. if there are 20,000 regi

stered cat owners how many dog owners are there?

1 answer:

alexandr1967 [171]3 years ago

7 0

40,000 Dog owners :3

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angela and neil are going to the movies they each bought a medium popcorn and neil got a small soft drink angela had a $10 gift

bazaltina [42]

$5.90 is my answer because its 19.3-9-4.4

6 0

3 years ago

Read 2 more answers

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

1

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

2

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

3

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

4

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$

$(a^2b^6)^\frac{1}{2}$

Rewrite to the half-power as a square root,

$\sqrt{a^2b^6}$

Simplify, divide all of the exponents by (2),

$ab^3$

7 0

3 years ago

A is a finite non-empty set. The domain for relation R is the power set of A.(Recall that the power set of A is the set of all s

siniylev [52]

Answer:

The answer is "Choice D"

Step-by-step explanation:

Determining the information:

For " $X \subseteq A$ " and " $Y \subseteq A$ ", $X$ relates to $Y$ when $X$ and $Y$ has the same cardinality. therefore, R does not have reflective:

For every " $X \subseteq A$ ", " $X= X$ " So, X not proper subset of $X$ . So, R does not havereflexive.

R does not have symmetry:

For every " $X \subseteq Y$ " ,then, " $Y \subset X$ " is not true because $X$ not relate to $Y$ . So, R is not symmetric.

R does not have antisymmetric:

When $X$ relates to $Y$ and $Y$ is relate to $X$ , then " $X \subset Y$ " and " $Y \subset X$ " $\to X=Y$

Therefore, R is anti-symmetric.

5 0

3 years ago

Who is the partial product of 28 and 42

Lana71 [14]

The partial products are: 42 x 28 = (40 + 2) x (20 + 8) = 40 x 20 + 40 x 8 + 2 x 20 + 2 x 8
= 800 + 320 + 40 + 16 Hope this helped.

6 0

3 years ago

A house and a lot are worth $210,000. If

xxTIMURxx [149]

Answer:

182000

Explanation :

H , house
L , lot

H + L = 210000
H = 6.5•L
(6.5L) + L = 210000
L = 28000

H = 6.5(28000) = 182000

7 0

3 years ago