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melisa1 [442]
3 years ago
7

A sample of 3 different calculators is randomly selected from a group containing 17 that are bad and 36 that are good. What is t

he probability that all three calculators are good?
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Probability of all 3  calculators being good = 0.971.

<u>Step-by-step explanation:</u>

We have , A sample of 3 different calculators is randomly selected from a group containing 17 that are bad and 36 that are good. In order to calculate that all 3 randomly selected calculators are good , let's calculate probability of all 3 being bad and subtracting value by 1. i.e. Probability of all 3 being good = 1 - Probability of all 3 being bad

⇒  Probability of all 3 being bad  = \frac{17}{53}×\frac{17}{53}×\frac{17}{53} =  4193/148877

∴Probability of all 3 being good = 1 - Probability of all 3 being bad

⇒ 1 - \frac{4193}{148877}

⇒\frac{144684}{148877}

∴Probability of all 3  calculators being good = 0.971.

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